Hi Krushna,

Modifying the default parameter in overidden function is not suggested.
Here actually show() version of derived is getting called. You can check
this if you modify the derived version of show()

show(int iVal=1000)
        {
            cout<<iVal<<endl;
            cout<<endl<<"Derived is called";
        }

regards,
--vikas

                      Krushna
                      <bkrushnaHOTMAIL To: DCOMDISCUSS.MICROSOFT.COM
                      .COM> cc:
                      Sent by: Subject: Re: behaviour of DllMain
                      Distributed
                      COM-Based Code
                      <DCOMDISCUSS.MIC
                      ROSOFT.COM>

                      29/01/2003 17:01
                      Please respond to
                      Distributed
                      COM-Based Code

Hi All,
Can Anybody tell me When deafult parameter of virtual function get resolved
and how?
for example I have 2 class
Class Base
{
public:
        virtual show(int iVal=100)
        {
            cout<<iVal<<endl;
        }
}

Class Derived : public Base
{
public:
        show(int iVal=1000)
        {
            cout<<iVal<<endl;
        }
}

Main
{
Base *ptr= new Derived;
ptr->show();
}

Output is 100 while debugging actually derived class function is getting
executed why ?

}
----- Original Message --

---
From: "Ximon Eighteen" <ximon_eighteen3B2.COM>
To: <DCOMDISCUSS.MICROSOFT.COM>
Sent: Wednesday, January 29, 2003 4:27 PM
Subject: Re: behaviour of DllMain
> > but then why the other call was made to DllMain ????
>
> There are four times that DllMain can be invoked. From the documentation
of
> DllMain:-
>
>   - DLL_PROCESS_ATTACH
>   - DLL_THREAD_ATTACH
>   - DLL_THREAD_DETACH
>   - DLL_PROCESS_DETACH
>
> In your case I presume you are seeing DLL_PROCESS_ATTACH followed by
> DLL_THREAD_ATTACH.
>
> Ximon Eighteen
>
> ----------------------------------------------------------------
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