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% stdout?

From: Cassio B. Caporal (cassioostec.com.br)
Date: Thu Nov 09 2006 - 10:37:33 CST

        Hey,

        I have problems to print '%' in stdout... Suppose code below:

                #include <stdio.h>

                main() {
                         char foo[] = "bar=30%\n";
                         fprintf(stdout, bar);
                }

        OpenBSD returns : bar=30
        Linux returns : bar=30%

        How can I solve this? Thanks,