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Re: % stdout?

From: Jason Dixon (jasondixongroup.net)
Date: Thu Nov 09 2006 - 10:59:12 CST

On Nov 9, 2006, at 11:37 AM, Cassio B. Caporal wrote:

> Hey,
>
> I have problems to print '%' in stdout... Suppose code below:
>
> #include <stdio.h>
>
> main() {
> char foo[] = "bar=30%\n";
> fprintf(stdout, bar);
> }
>
> OpenBSD returns : bar=30
> Linux returns : bar=30%
>
> How can I solve this? Thanks,

$ cat foo.c
#include <stdio.h>

main() {
         char foo[] = "bar=30%%\n";
         fprintf(stdout, foo);
}
$ gcc foo.c -o foo
$ ./foo
bar=30%

--
Jason Dixon
DixonGroup Consulting
http://www.dixongroup.net