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Re: % stdout?

From: Andreas Kahari (andreas.kaharigmail.com)
Date: Thu Nov 09 2006 - 11:16:55 CST

Suppose the data in 'foo' comes from user input:

#include <stdio.h>

main()
{
    char foo[] = "bar=30%\n";
    fprintf(stdout, "%s", foo);
}

Andreas

On 09/11/06, Jason Dixon <jasondixongroup.net> wrote:
> On Nov 9, 2006, at 11:37 AM, Cassio B. Caporal wrote:
>
> > Hey,
> >
> > I have problems to print '%' in stdout... Suppose code below:
> >
> > #include <stdio.h>
> >
> > main() {
> > char foo[] = "bar=30%\n";
> > fprintf(stdout, bar);
> > }
> >
> > OpenBSD returns : bar=30
> > Linux returns : bar=30%
> >
> > How can I solve this? Thanks,
>
> $ cat foo.c
> #include <stdio.h>
>
> main() {
> char foo[] = "bar=30%%\n";
> fprintf(stdout, foo);
> }
> $ gcc foo.c -o foo
> $ ./foo
> bar=30%
>
>
> --
> Jason Dixon
> DixonGroup Consulting
> http://www.dixongroup.net
>
>

--
Andreas Kahari
Somewhere in the general Cambridge area, UK