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php-general-digest-help_at_lists.php.net
Date: Sun Feb 02 2003 - 07:09:31 CST

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    php-general Digest 2 Feb 2003 13:09:31 -0000 Issue 1859

    Topics (messages 133941 through 133989):

    Re: Screen Size detect??
            133941 by: Martin

    Re: using <input> tags with php
            133942 by: Philip Olson
            133956 by: Sunfire
            133967 by: David Freeman
            133971 by: David Freeman
            133982 by: Edwin Boersma

    Re: Loading CSV data into MySQL
            133943 by: John W. Holmes
            133954 by: Jason Sheets
            133980 by: Edwin Boersma

    emulate callback error for php3
            133944 by: electroteque
            133962 by: electroteque

    Re: Register globals on and off
            133945 by: Pat Johnston
            133973 by: Philip Olson

    Re: Passing Variables
            133946 by: Beauford.2002

    Re: PHP.ini help on Linux
            133947 by: Michael Mauch
            133966 by: Nicole
            133968 by: Nicole

    Re: 4.3 Install on Solaris
            133948 by: J Smith
            133950 by: Dan Lowe

    Base64 Encode
            133949 by: Stephen
            133970 by: Evan Nemerson

    Using SELECT and MULTIPLE in a form
            133951 by: James Kaufman
            133952 by: John Nichel
            133953 by: Tom Rogers

    Line Number function?
            133955 by: Benjamin Smith
            133957 by: Steven Balthazor
            133969 by: Michael Sims
            133975 by: Philip Olson

    Turn off PHP for certain directories?
            133958 by: Benjamin Smith
            133960 by: Timothy Hitchens \(HiTCHO\)
            133985 by: Tom Rogers
            133989 by: Ernest E Vogelsinger

    php and Mac running 8.6
            133959 by: Bobbi-Lea
            133961 by: Timothy Hitchens \(HiTCHO\)
            133979 by: Justin French

    help with script!!!
            133963 by: Karl James
            133972 by: Hugh Danaher
            133974 by: Philip Olson
            133976 by: David Freeman
            133977 by: Philip Olson

    .dat file
            133964 by: Karl James

    perl regex help
            133965 by: Alex

    Re: any change to see php source?
            133978 by: qt
            133983 by: Edwin Boersma

    Trouble with Exec
            133981 by: Nicole

    Re: help needed building query string based on which form fields that are filled.
            133984 by: Edwin Boersma

    Retrieving field name of Database
            133986 by: Davy Obdam

    processing form with unknown number of checkboxes, each with a unknown name.
            133987 by: anders thoresson
            133988 by: Tim Ward

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    ----------------------------------------------------------------------

    attached mail follows:


    you can create a form with hidden fields like this

     <script language="JavaScript">

        document.screendata.height.value=screen.height;
        document.screendata.width.value=screen.width;
        screendata.submit();
    </script>

    <form method="post" action="index.php" name="screendata">
    <input type="hidden" name="height">
    <input type="hidden" name="width">
    </form>

    bye

    "Nigel Powell" <guchthatdog.demon.co.uk> escribió en el mensaje
    news:AA770E0A-3601-11D7-9762-003065E3C78Athatdog.demon.co.uk...
    >
    > On a slight side note to this, how can you pass javascript variables to
    > PHP via POST?
    >
    > Newbie Powell
    >
    > On Saturday, February 1, 2003, at 12:21 PM,
    > php-general-digest-helplists.php.net wrote:
    >
    > > From: "Sean Malloy" <seanelement.net.au>
    > > Date: Sat Feb 1, 2003 6:48:26 AM Europe/London
    > > To: "Dade Register" <dade49yahoo.com>, <php-generallists.php.net>
    > > Subject: RE: [PHP] Screen Size detect??
    > >
    > >
    > > Create index.htm;
    > >
    > > <script language="JavaScript">
    > > var width = screen.width;
    > > var height = screen.height;
    > > window.location = 'index.php?width=' + width + '&height=' + height;
    > > </script>
    > >
    > > and in index.php
    > >
    > > $width = $_GET['width'];
    > > $height = $_GET['height'];
    > >
    > >
    > > etc etc
    >

    attached mail follows:


    On Sat, 1 Feb 2003, Sunfire wrote:

    > hi.. i took your idea...
    > i put the error reporting code at the top of the script and ran it as the
    > problem was still there to see what would happen.. instead i get 0 messages
    > from the reporting system and all i get is the last 7 chars of the print
    > line and the }?> at the end of the script... so for instance if i do:
    > print("<input type=\"text\" name=\"company\" value=$new['company']\n");
    > or any variance of that statement changing around the \" and apostrophes
    > around to try different things all i get is the rest of the script starting
    > from the \n all the way to the rest of the script where it says }?> at the
    > end dont know if this is a bug or not but its getting hard to figure out
    > what the problem with my echo or print statements are...
    > here is the whole script:
    > its supposed to get all fields and then display in input text boxes the
    > current values in that certain record i know i missed some stuff in it with
    > the query but at this point was supposed to be a test to see if i could even
    > put it in the box in the first place... but here is the code:

    Please step back, slow down, and write your question
    in a short concise format. I have no clue what the
    above means.

    > <html>
    > <head>
    > <title>edit member</title>
    >
    > </head>
    >
    > <form action=edit1.php method=post>
    > pick some of these:<br>
    > <?php
    > error_reporting(E_ALL);
    > mysql_connect("192.4.5.6", "root", "");
    > mysql_select_db("wata");
    > $result=mysql_query("select * from members where company like 'test'");
    > while($row=mysql_fetch_array($result)){
    > print("<input type=text name=company value=\"$row[company\"]>\n\n");

    // Try this instead, see also: htmlspecialchars()*
    print "<input type='text' name='company' value='{$row['company']}'>";

    Regards,
    Philip

    * http://www.php.net/manual/en/faq.html.php#faq.html.encoding

    > }
    > ?>
    > <input type="submit" value="send">
    > </form>
    > </html>
    >
    > /*end*/
    > any changes to make it work would be appreciated...tnx
    >
    >
    > ----- Original Message -----
    > From: "Philip Olson" <philipcornado.com>
    > To: "Sunfire" <rusty_81msn.com>
    > Cc: <php-generallists.php.net>; <janetvalade.com>
    > Sent: Saturday, February 01, 2003 6:48 PM
    > Subject: Re: [PHP] using <input> tags with php (IMPORTANT READ)
    >
    >
    > >
    > > On Sat, 1 Feb 2003, Sunfire wrote:
    > >
    > > > if i do this:
    > > > /*all the mysql login stuff here*/
    > > >
    > > > $query=mysql_query("select * from members");
    > > > while($new=mysql_fetch_array($query)){
    > > > echo "$new['company']";
    > > > /*so on through the field list*/
    > > > }
    > > > on output all i get is the title with a submit button..
    > > > otherwise blank..
    > >
    > > There is a bug in PHP 4.3.0 regarding the use of arrays
    > > in strings. The following gave a parse error before
    > > PHP 4.3.0:
    > >
    > > print "Do not do this: $arr['key']";
    > >
    > > Now it gives an E_NOTICE error due to changes to the string
    > > scanner. In PHP 4.3.1 it will no longer give a bogus E_NOTICE
    > > and instead it will work (no parse error either). Surrounding
    > > the array with {braces} in the string works regardless, so:
    > >
    > > print "You can do this: {$arr['key']}";
    > >
    > > Regarding this question, don't write it like that but instead
    > > do the following (no quotes needed):
    > >
    > > echo $new['company'];
    > >
    > > For those wondering about this bug, see:
    > >
    > > http://bugs.php.net/bug.php?id=21820
    > >
    > > The string documentation has been updated to demonstrate
    > > the array in string phenomena (except the bug hasn't been
    > > mentioned as I'm waiting for it to be committed first).
    > >
    > > http://www.php.net/types.string
    > >
    > > Sunfire, you aren't seeing this E_NOTICE error because your
    > > error level is turned down (by default). Put this on top
    > > of your script to see them all:
    > >
    > > error_reporting(E_ALL);
    > >
    > > Regards,
    > > Philip
    > >
    > >
    > > > same thing with fetch_object()...and i have 1 row in the members
    > table..im
    > > > sort of confused now that it doesnt work for a wierd reason
    > > >
    > > > any better ideas on how to get the stuff out of the table and into vars?
    > > > maybe im doing it wrong
    > > >
    > > >
    > > > ----- Original Message -----
    > > > From: <janetvalade.com>
    > > > To: <php-generallists.php.net>
    > > > Sent: Saturday, February 01, 2003 5:33 PM
    > > > Subject: Re: [PHP] using <input> tags with php
    > > >
    > > >
    > > > > In a message dated 2/1/2003 2:02:06 PM Pacific Standard Time,
    > > > > rusty_81msn.com writes:
    > > > >
    > > > > >i tried getting the values into vars using fetch_array/fetch_object
    > and
    > > > > >fetch_row and tried to put them in variables but for some odd reason
    > it
    > > > > >really doesnt work because when i try to use the vars in the value
    > > > section
    > > > > >instead of printing in the edit box the content of the variable i
    > usually
    > > > > >end up with "?>", ">", "<?php", or "}?>" instead... any reason this
    > shows
    > > > > >up? and when i do:
    > > > > >echo "<input type=text name=$name value='$new_var'>";
    > > > > >then on the web page i end up with some thing like this instead of
    > the
    > > > edit
    > > > > >box:
    > > > > >">";;">
    > > > > >}?>
    > > > > >any reason for that?
    > > > >
    > > > > It sounds like $name and/or $new_var may be empty. Did you echo the
    > > > variables
    > > > > before using them in your form to check whether the values from the
    > > > database
    > > > > are actually in the variables?
    > > > >
    > > > > Janet
    > > > >
    > > > > --
    > > > > PHP General Mailing List (http://www.php.net/)
    > > > > To unsubscribe, visit: http://www.php.net/unsub.php
    > > > >
    > > > >
    > > >
    > > >
    > > > ---
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    > > > Checked by AVG anti-virus system (http://www.grisoft.com).
    > > > Version: 6.0.443 / Virus Database: 248 - Release Date: 1/10/2003
    > > >
    > > >
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    > > > To unsubscribe, visit: http://www.php.net/unsub.php
    > > >
    > >
    > >
    > >
    > > --
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    > >
    > >
    >
    >
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    >
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    > To unsubscribe, visit: http://www.php.net/unsub.php
    >

    attached mail follows:


    ok let me try this question thing again...

    i am having a problem using <input> tags by using current values kept in a
    mysql table. how do you get the values out of the table and into a form so
    they show as the value= part of the tag?
    i tried just aabout everything and it doesnt work even htmlspecialchars()
    doesnt work.. all i get for output on the page is the rest of the script
    printed on the screen after the value= part of the tag..is there any way to
    fix it?

    ----- Original Message -----
    From: "Philip Olson" <philipcornado.com>
    To: "Sunfire" <rusty_81msn.com>
    Cc: <php-generallists.php.net>; <janetvalade.com>
    Sent: Saturday, February 01, 2003 8:01 PM
    Subject: Re: [PHP] using <input> tags with php

    > On Sat, 1 Feb 2003, Sunfire wrote:
    >
    > > hi.. i took your idea...
    > > i put the error reporting code at the top of the script and ran it as
    the
    > > problem was still there to see what would happen.. instead i get 0
    messages
    > > from the reporting system and all i get is the last 7 chars of the print
    > > line and the }?> at the end of the script... so for instance if i do:
    > > print("<input type=\"text\" name=\"company\" value=$new['company']\n");
    > > or any variance of that statement changing around the \" and apostrophes
    > > around to try different things all i get is the rest of the script
    starting
    > > from the \n all the way to the rest of the script where it says }?> at
    the
    > > end dont know if this is a bug or not but its getting hard to figure out
    > > what the problem with my echo or print statements are...
    > > here is the whole script:
    > > its supposed to get all fields and then display in input text boxes the
    > > current values in that certain record i know i missed some stuff in it
    with
    > > the query but at this point was supposed to be a test to see if i could
    even
    > > put it in the box in the first place... but here is the code:
    >
    > Please step back, slow down, and write your question
    > in a short concise format. I have no clue what the
    > above means.
    >
    > > <html>
    > > <head>
    > > <title>edit member</title>
    > >
    > > </head>
    > >
    > > <form action=edit1.php method=post>
    > > pick some of these:<br>
    > > <?php
    > > error_reporting(E_ALL);
    > > mysql_connect("192.4.5.6", "root", "");
    > > mysql_select_db("wata");
    > > $result=mysql_query("select * from members where company like 'test'");
    > > while($row=mysql_fetch_array($result)){
    > > print("<input type=text name=company value=\"$row[company\"]>\n\n");
    >
    > // Try this instead, see also: htmlspecialchars()*
    > print "<input type='text' name='company' value='{$row['company']}'>";
    >
    > Regards,
    > Philip
    >
    > * http://www.php.net/manual/en/faq.html.php#faq.html.encoding
    >
    >
    > > }
    > > ?>
    > > <input type="submit" value="send">
    > > </form>
    > > </html>
    > >
    > > /*end*/
    > > any changes to make it work would be appreciated...tnx
    > >
    > >
    > > ----- Original Message -----
    > > From: "Philip Olson" <philipcornado.com>
    > > To: "Sunfire" <rusty_81msn.com>
    > > Cc: <php-generallists.php.net>; <janetvalade.com>
    > > Sent: Saturday, February 01, 2003 6:48 PM
    > > Subject: Re: [PHP] using <input> tags with php (IMPORTANT READ)
    > >
    > >
    > > >
    > > > On Sat, 1 Feb 2003, Sunfire wrote:
    > > >
    > > > > if i do this:
    > > > > /*all the mysql login stuff here*/
    > > > >
    > > > > $query=mysql_query("select * from members");
    > > > > while($new=mysql_fetch_array($query)){
    > > > > echo "$new['company']";
    > > > > /*so on through the field list*/
    > > > > }
    > > > > on output all i get is the title with a submit button..
    > > > > otherwise blank..
    > > >
    > > > There is a bug in PHP 4.3.0 regarding the use of arrays
    > > > in strings. The following gave a parse error before
    > > > PHP 4.3.0:
    > > >
    > > > print "Do not do this: $arr['key']";
    > > >
    > > > Now it gives an E_NOTICE error due to changes to the string
    > > > scanner. In PHP 4.3.1 it will no longer give a bogus E_NOTICE
    > > > and instead it will work (no parse error either). Surrounding
    > > > the array with {braces} in the string works regardless, so:
    > > >
    > > > print "You can do this: {$arr['key']}";
    > > >
    > > > Regarding this question, don't write it like that but instead
    > > > do the following (no quotes needed):
    > > >
    > > > echo $new['company'];
    > > >
    > > > For those wondering about this bug, see:
    > > >
    > > > http://bugs.php.net/bug.php?id=21820
    > > >
    > > > The string documentation has been updated to demonstrate
    > > > the array in string phenomena (except the bug hasn't been
    > > > mentioned as I'm waiting for it to be committed first).
    > > >
    > > > http://www.php.net/types.string
    > > >
    > > > Sunfire, you aren't seeing this E_NOTICE error because your
    > > > error level is turned down (by default). Put this on top
    > > > of your script to see them all:
    > > >
    > > > error_reporting(E_ALL);
    > > >
    > > > Regards,
    > > > Philip
    > > >
    > > >
    > > > > same thing with fetch_object()...and i have 1 row in the members
    > > table..im
    > > > > sort of confused now that it doesnt work for a wierd reason
    > > > >
    > > > > any better ideas on how to get the stuff out of the table and into
    vars?
    > > > > maybe im doing it wrong
    > > > >
    > > > >
    > > > > ----- Original Message -----
    > > > > From: <janetvalade.com>
    > > > > To: <php-generallists.php.net>
    > > > > Sent: Saturday, February 01, 2003 5:33 PM
    > > > > Subject: Re: [PHP] using <input> tags with php
    > > > >
    > > > >
    > > > > > In a message dated 2/1/2003 2:02:06 PM Pacific Standard Time,
    > > > > > rusty_81msn.com writes:
    > > > > >
    > > > > > >i tried getting the values into vars using
    fetch_array/fetch_object
    > > and
    > > > > > >fetch_row and tried to put them in variables but for some odd
    reason
    > > it
    > > > > > >really doesnt work because when i try to use the vars in the
    value
    > > > > section
    > > > > > >instead of printing in the edit box the content of the variable i
    > > usually
    > > > > > >end up with "?>", ">", "<?php", or "}?>" instead... any reason
    this
    > > shows
    > > > > > >up? and when i do:
    > > > > > >echo "<input type=text name=$name value='$new_var'>";
    > > > > > >then on the web page i end up with some thing like this instead
    of
    > > the
    > > > > edit
    > > > > > >box:
    > > > > > >">";;">
    > > > > > >}?>
    > > > > > >any reason for that?
    > > > > >
    > > > > > It sounds like $name and/or $new_var may be empty. Did you echo
    the
    > > > > variables
    > > > > > before using them in your form to check whether the values from
    the
    > > > > database
    > > > > > are actually in the variables?
    > > > > >
    > > > > > Janet
    > > > > >
    > > > > > --
    > > > > > PHP General Mailing List (http://www.php.net/)
    > > > > > To unsubscribe, visit: http://www.php.net/unsub.php
    > > > > >
    > > > > >
    > > > >
    > > > >
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    > > > > Outgoing mail is certified Virus Free.
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    > > > > Version: 6.0.443 / Virus Database: 248 - Release Date: 1/10/2003
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    > > >
    > > >
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    >

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    Version: 6.0.443 / Virus Database: 248 - Release Date: 1/10/2003
    

    attached mail follows:


    > i want to set up a form that will load values from a table > and make them the > "value" of the edit box... then when people press an update > button then all > of the stuff that changes from the record already in the table gets > changed... anybody know how to make it where you can get the > values out of a > table and make them the default value of a input field...?

    What is it that you're having trouble with? The logic to do what you want? The actual code to load values from a table (a database table I presume)? The correct HTML that you need to have values in a form field? The code to update your database with information from the form?

    Perhaps if you got started with working out what you want to do and then ask questions.

    Failing that, I'd be happy to write it for you. Of course, I'll charge my normal hourly rate to do so...

    CYA, Dave

    attached mail follows:


    > i am having a problem using <input> tags by using current > values kept in a mysql table. how do you get the values out of the table and > into a form so they show as the value= part of the tag?

    Start by making a basic test:

    <?PHP $some_string = "some string"; echo "<input type=\"text\" name=\"some_string\" value=\"$some_string\" size=20>"; ?>

    or you could try this:

    <?PHP $some_string = "some string"; ?> <input type="text" name="some_string" value="<?=$some_string?>" size=20>

    Either should work.

    Rinse and repeat as necessary.

    CYA, Dave

    attached mail follows:


    Are you absolutely sure that the query gives result? Try and add "or die (mysql_error())" behind mysql_connect, mysql_select_db and mysql_query. For the rest, it looks pretty good to me....

    Sunfire wrote: > ok let me try this question thing again... > > i am having a problem using <input> tags by using current values kept in a > mysql table. how do you get the values out of the table and into a form so > they show as the value= part of the tag? > i tried just aabout everything and it doesnt work even htmlspecialchars() > doesnt work.. all i get for output on the page is the rest of the script > printed on the screen after the value= part of the tag..is there any way to > fix it? > > > ----- Original Message ----- > From: "Philip Olson" <philipcornado.com> > To: "Sunfire" <rusty_81msn.com> > Cc: <php-generallists.php.net>; <janetvalade.com> > Sent: Saturday, February 01, 2003 8:01 PM > Subject: Re: [PHP] using <input> tags with php > > > >>On Sat, 1 Feb 2003, Sunfire wrote: >> >> >>>hi.. i took your idea... >>>i put the error reporting code at the top of the script and ran it as >> > the > >>>problem was still there to see what would happen.. instead i get 0 >> > messages > >>>from the reporting system and all i get is the last 7 chars of the print >>>line and the }?> at the end of the script... so for instance if i do: >>>print("<input type=\"text\" name=\"company\" value=$new['company']\n"); >>>or any variance of that statement changing around the \" and apostrophes >>>around to try different things all i get is the rest of the script >> > starting > >>>from the \n all the way to the rest of the script where it says }?> at >> > the > >>>end dont know if this is a bug or not but its getting hard to figure out >>>what the problem with my echo or print statements are... >>>here is the whole script: >>>its supposed to get all fields and then display in input text boxes the >>>current values in that certain record i know i missed some stuff in it >> > with > >>>the query but at this point was supposed to be a test to see if i could >> > even > >>>put it in the box in the first place... but here is the code: >> >>Please step back, slow down, and write your question >>in a short concise format. I have no clue what the >>above means. >> >> >>><html> >>><head> >>><title>edit member</title> >>> >>></head> >>> >>><form action=edit1.php method=post> >>>pick some of these:<br> >>><?php >>>error_reporting(E_ALL); >>>mysql_connect("192.4.5.6", "root", ""); >>>mysql_select_db("wata"); >>>$result=mysql_query("select * from members where company like 'test'"); >>>while($row=mysql_fetch_array($result)){ >>>print("<input type=text name=company value=\"$row[company\"]>\n\n"); >> >>// Try this instead, see also: htmlspecialchars()* >>print "<input type='text' name='company' value='{$row['company']}'>"; >> >>Regards, >>Philip >> >>* http://www.php.net/manual/en/faq.html.php#faq.html.encoding >> >> >> >>>} >>>?> >>><input type="submit" value="send"> >>></form> >>></html> >>> >>>/*end*/ >>>any changes to make it work would be appreciated...tnx >>> >>> >>>----- Original Message ----- >>>From: "Philip Olson" <philipcornado.com> >>>To: "Sunfire" <rusty_81msn.com> >>>Cc: <php-generallists.php.net>; <janetvalade.com> >>>Sent: Saturday, February 01, 2003 6:48 PM >>>Subject: Re: [PHP] using <input> tags with php (IMPORTANT READ) >>> >>> >>> >>>>On Sat, 1 Feb 2003, Sunfire wrote: >>>> >>>> >>>>>if i do this: >>>>>/*all the mysql login stuff here*/ >>>>> >>>>>$query=mysql_query("select * from members"); >>>>>while($new=mysql_fetch_array($query)){ >>>>>echo "$new['company']"; >>>>>/*so on through the field list*/ >>>>>} >>>>>on output all i get is the title with a submit button.. >>>>>otherwise blank.. >>>> >>>> There is a bug in PHP 4.3.0 regarding the use of arrays >>>> in strings. The following gave a parse error before >>>> PHP 4.3.0: >>>> >>>> print "Do not do this: $arr['key']"; >>>> >>>> Now it gives an E_NOTICE error due to changes to the string >>>> scanner. In PHP 4.3.1 it will no longer give a bogus E_NOTICE >>>> and instead it will work (no parse error either). Surrounding >>>> the array with {braces} in the string works regardless, so: >>>> >>>> print "You can do this: {$arr['key']}"; >>>> >>>> Regarding this question, don't write it like that but instead >>>> do the following (no quotes needed): >>>> >>>> echo $new['company']; >>>> >>>> For those wondering about this bug, see: >>>> >>>> http://bugs.php.net/bug.php?id=21820 >>>> >>>> The string documentation has been updated to demonstrate >>>> the array in string phenomena (except the bug hasn't been >>>> mentioned as I'm waiting for it to be committed first). >>>> >>>> http://www.php.net/types.string >>>> >>>> Sunfire, you aren't seeing this E_NOTICE error because your >>>> error level is turned down (by default). Put this on top >>>> of your script to see them all: >>>> >>>> error_reporting(E_ALL); >>>> >>>> Regards, >>>> Philip >>>> >>>> >>>> >>>>>same thing with fetch_object()...and i have 1 row in the members >>>> >>>table..im >>> >>>>>sort of confused now that it doesnt work for a wierd reason >>>>> >>>>>any better ideas on how to get the stuff out of the table and into >>>> > vars? > >>>>>maybe im doing it wrong >>>>> >>>>> >>>>>----- Original Message ----- >>>>>From: <janetvalade.com> >>>>>To: <php-generallists.php.net> >>>>>Sent: Saturday, February 01, 2003 5:33 PM >>>>>Subject: Re: [PHP] using <input> tags with php >>>>> >>>>> >>>>> >>>>>>In a message dated 2/1/2003 2:02:06 PM Pacific Standard Time, >>>>>>rusty_81msn.com writes: >>>>>> >>>>>> >>>>>>>i tried getting the values into vars using >>>>>> > fetch_array/fetch_object > >>>and >>> >>>>>>>fetch_row and tried to put them in variables but for some odd >>>>>> > reason > >>>it >>> >>>>>>>really doesnt work because when i try to use the vars in the >>>>>> > value > >>>>>section >>>>> >>>>>>>instead of printing in the edit box the content of the variable i >>>>>> >>>usually >>> >>>>>>>end up with "?>", ">", "<?php", or "}?>" instead... any reason >>>>>> > this > >>>shows >>> >>>>>>>up? and when i do: >>>>>>>echo "<input type=text name=$name value='$new_var'>"; >>>>>>>then on the web page i end up with some thing like this instead >>>>>> > of > >>>the >>> >>>>>edit >>>>> >>>>>>>box: >>>>>>>">";;"> >>>>>>>}?> >>>>>>>any reason for that? >>>>>> >>>>>>It sounds like $name and/or $new_var may be empty. Did you echo >>>>> > the > >>>>>variables >>>>> >>>>>>before using them in your form to check whether the values from >>>>> > the > >>>>>database >>>>> >>>>>>are actually in the variables? >>>>>> >>>>>>Janet >>>>>> >>>>>>-- >>>>>>PHP General Mailing List (http://www.php.net/) >>>>>>To unsubscribe, visit: http://www.php.net/unsub.php >>>>>> >>>>>> >>>>> >>>>> >>>>>--- >>>>>Outgoing mail is certified Virus Free. >>>>>Checked by AVG anti-virus system (http://www.grisoft.com). >>>>>Version: 6.0.443 / Virus Database: 248 - Release Date: 1/10/2003 >>>>> >>>>> >>>>>-- >>>>>PHP General Mailing List (http://www.php.net/) >>>>>To unsubscribe, visit: http://www.php.net/unsub.php >>>>> >>>> >>>> >>>> >>>>-- >>>>PHP General Mailing List (http://www.php.net/) >>>>To unsubscribe, visit: http://www.php.net/unsub.php >>>> >>>> >>> >>> >>>--- >>>Outgoing mail is certified Virus Free. >>>Checked by AVG anti-virus system (http://www.grisoft.com). >>>Version: 6.0.443 / Virus Database: 248 - Release Date: 1/10/2003 >>> >>> >>>-- >>>PHP General Mailing List (http://www.php.net/) >>>To unsubscribe, visit: http://www.php.net/unsub.php >>> >> >> >>-- >>PHP General Mailing List (http://www.php.net/) >>To unsubscribe, visit: http://www.php.net/unsub.php >> >> > > > > --- > Outgoing mail is certified Virus Free. > Checked by AVG anti-virus system (http://www.grisoft.com). > Version: 6.0.443 / Virus Database: 248 - Release Date: 1/10/2003 >

    attached mail follows:


    > On Sat, 2003-02-01 at 17:25, John W. Holmes wrote: > > > I'm loading a .csv file into MySQL, done it a million times but for > > some > > > reason it is scrambling the row order. All the fields are making it in > > > correctly but the order of the rows seems to end up totally random. > > I've > > > done this a million times and never saw this.. > > > > So? > > > > Why does it matter to you what order the rows are in the database, as > > long as the right data is there? The order is irrelevant. > > > > Because in this instance I need it to come out in the order it is > actually in.

    Then use an ORDER BY in your query. If you're relying on the database to spit out rows in the order they went in, then you're wrong.

    ---John W. Holmes...

    PHP Architect - A monthly magazine for PHP Professionals. Get your copy today. http://www.phparch.com/

    attached mail follows:


    You could create a integer column with an autoincrement flag, then order the rows by this column, that should give you the data in the order it was inserted into the db. Depending on your database there are other ways to do it.

    Jason On Sat, 2003-02-01 at 18:07, John W. Holmes wrote: > > On Sat, 2003-02-01 at 17:25, John W. Holmes wrote: > > > > I'm loading a .csv file into MySQL, done it a million times but > for > > > some > > > > reason it is scrambling the row order. All the fields are making > it in > > > > correctly but the order of the rows seems to end up totally > random. > > > I've > > > > done this a million times and never saw this.. > > > > > > So? > > > > > > Why does it matter to you what order the rows are in the database, > as > > > long as the right data is there? The order is irrelevant. > > > > > > > Because in this instance I need it to come out in the order it is > > actually in. > > Then use an ORDER BY in your query. If you're relying on the database to > spit out rows in the order they went in, then you're wrong. > > ---John W. Holmes... > > PHP Architect - A monthly magazine for PHP Professionals. Get your copy > today. http://www.phparch.com/ > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php

    attached mail follows:


    Or add a "insert_date" column of type "timestamp" to the database. This will automatically store the time of insertion. Then use ORDER BY insert_date.

    Edwin

    Jason Sheets wrote: > You could create a integer column with an autoincrement flag, then order > the rows by this column, that should give you the data in the order it > was inserted into the db. Depending on your database there are other > ways to do it. > > Jason > On Sat, 2003-02-01 at 18:07, John W. Holmes wrote: > >>>On Sat, 2003-02-01 at 17:25, John W. Holmes wrote: >>> >>>>>I'm loading a .csv file into MySQL, done it a million times but >>>> >>for >> >>>>some >>>> >>>>>reason it is scrambling the row order. All the fields are making >>>> >>it in >> >>>>>correctly but the order of the rows seems to end up totally >>>> >>random. >> >>>>I've >>>> >>>>>done this a million times and never saw this.. >>>> >>>>So? >>>> >>>>Why does it matter to you what order the rows are in the database, >>> >>as >> >>>>long as the right data is there? The order is irrelevant. >>>> >>> >>>Because in this instance I need it to come out in the order it is >>>actually in. >> >>Then use an ORDER BY in your query. If you're relying on the database to >>spit out rows in the order they went in, then you're wrong. >> >>---John W. Holmes... >> >>PHP Architect - A monthly magazine for PHP Professionals. Get your copy >>today. http://www.phparch.com/ >> >> >> >>-- >>PHP General Mailing List (http://www.php.net/) >>To unsubscribe, visit: http://www.php.net/unsub.php > >

    attached mail follows:


    hi sorry to ask so many questions but i have now realised that php3 doesnt handle the callback error handling so i can return the line and file of the error into a function is there a way to emulate this in php3 ?

    attached mail follows:


    to be a bit less vague , i have a db query wrapper function, and checks for mysql errors if there is one it needs to catch it to a callback function although php3 doesnt handle callback functions so you have to give it the line and file, is there anyway i can try and get away from putting the line and file in the function like this ?

    $query = $db->query("select * from artists where artistI=1",__LINE__,__FILE__);

    "Electroteque" <danielelectroteque.org> wrote in message news:20030202021108.58744.qmailpb1.pair.com... > hi sorry to ask so many questions but i have now realised that php3 doesnt > handle the callback error handling so i can return the line and file of the > error into a function is there a way to emulate this in php3 ? > >

    attached mail follows:


    I've read that an include file in each of your pages with the lines below should do the trick for you with register_globals OFF..

    Not sure if this is a valid way to go though...

    <?php extract($_SERVER); extract($_ENV); extract($_GET); extract($_POST); extract($_REQUEST); ?>

    Regards, Pat

    "Davy Obdam" <infodavyobdam.com> wrote in message news:3E38CBAF.1010501davyobdam.com... > Hello people, > > On my development machine (win XP/Apache 2.0.44/PHP 4.3.0/MySQL 3.23.55) > i have several websites that i made some time ago that require register > globals to be On in the php.ini. Ofcourse i know thats not a good idea > at all for security, but rewriting all this code is not an option. > However in my php.ini i have set register globals to Off because that > better. Is it possible to configure my webserver/php so that only those > sites that require register globals to be On have that setting, for > instance in a .htacces file?? Any help is appreciated:-) > > Best regards, > > Davy Obdam > mailto:infodavyobdam.com > >

    attached mail follows:


    On Sun, 2 Feb 2003, Pat Johnston wrote:

    > I've read that an include file in each of your pages with the lines below > should do the trick for you with register_globals OFF.. > > Not sure if this is a valid way to go though... > > <?php > extract($_SERVER); > extract($_ENV); > extract($_GET); > extract($_POST); > extract($_REQUEST); > ?>

    Whoever told you this should be shot as this is an enormous security hole! The above is a security hole much larger than register_globals could ever hope to be. That and it's silly to attempt to mimic register_globals at runtime.

    The above is insecure in that it will overwrite web server variables ($_SERVER) with request variables such as those from $_GET. This is TERRIBLE!!! Just imagine this as just an example:

    http://www.example.com/a.php?PHP_SELF=http://www.foo.com

    In the above scenerio, this would create $PHP_SELF first from $_SERVER then it'd be overwritten by the $_GET and than by the $_REQUEST that had the GET in it. So this makes it inefficient and insecure :) A better example exists but anyway this should show a nice point (like maybe PHP_AUTH_PW or REMOTE_USER).

    Anyway, sorry for the rant but it's just that whoever told you that should not tell anyone anything related to this topic.

    The best options are: a) rewrite the code or b) set register_globals with .htaccess or php.ini or in virtualhost in httpd.conf

    http://www.php.net/manual/en/configuration.changes.php

    Now if you must set it at runtime (please do not do this) then you could try this:

    // THIS IS NOT RECOMMENDED if (!ini_get('register_globals')) { $types_to_register = array('GET','POST','COOKIE', 'SESSION','SERVER'); foreach ($types_to_register as $type) { if (count(${'HTTP_' . $type . '_VARS'}) > 0) { extract(${'HTTP_' . $type . '_VARS'}, EXTR_OVERWRITE); } } } // THIS IS NOT RECOMMENDED

    Although it doesn't depend on the variables_order directive like register_globals does, it is flexible. Keep in mind that variables are written from first to last so you certainly don't want GET coming after SERVER.

    Regards, Philip

    > "Davy Obdam" <infodavyobdam.com> wrote in message > news:3E38CBAF.1010501davyobdam.com... > > Hello people, > > > > On my development machine (win XP/Apache 2.0.44/PHP 4.3.0/MySQL 3.23.55) > > i have several websites that i made some time ago that require register > > globals to be On in the php.ini. Ofcourse i know thats not a good idea > > at all for security, but rewriting all this code is not an option. > > However in my php.ini i have set register globals to Off because that > > better. Is it possible to configure my webserver/php so that only those > > sites that require register globals to be On have that setting, for > > instance in a .htacces file?? Any help is appreciated:-) > > > > Best regards, > > > > Davy Obdam > > mailto:infodavyobdam.com > > > > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >

    attached mail follows:


    Perfect. Thanks.

    ----- Original Message ----- From: "Philip Olson" <philipcornado.com> To: "Beauford.2002" <beauford.2002rogers.com> Cc: "PHP General" <php-generallists.php.net> Sent: Saturday, February 01, 2003 2:22 PM Subject: Re: [PHP] Passing Variables

    > On Sat, 1 Feb 2003, Beauford.2002 wrote: > > > Hi, > > > > Is there a way to pass a variable to a PHP script without using a form? I > > want to put several links on my main page that when clicked on goes to a PHP > > script - depending on what link was selected, will determine what part of > > the PHP script gets executed. > > Yes, use GET: > > <a href="foo.php?fruit=apple">eat an apple</a> > > See also if() and switch() > > http://www.php.net/else > http://www.php.net/switch > http://www.php.net/variables.external > > print $_GET['fruit']; > > Regards, > Philip > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >

    attached mail follows:


    Nicole <430ntr3kaeontrek.com> wrote: > I am having trouble doing things with PHP such as use the exec, system, > etc. functions. I can't seem to find the correct php.ini to turn safe_mode > off. The one file I did find has safe_mode turned off. When I view phpinfo() > it shows the global column with safe_mode off, but for the local column, it > is on. Is there a local php.ini file for each site?

    No. But the values found in the global php.ini can be changed in Apache's httpd.conf and in .htaccess files. See <http://www.php.net/manual/en/configuration.changes.php>.

    You can have a .htaccess file in every directory to pass additional options to Apache (and mod_php). A .htaccess is used for the directory where it resides and for all subdirectories.

    Try "locate .htaccess" or "find / -name .htaccess".

    > I need to call a script to run in the background and I want to be able to > use exec() to call it. Is there an alternative way to do this without > bothering with the safe_mode value? i'd prefer to leave safe_mode on; but at > the same rate, I am the only one with access to the server as it is my > dedicated server.

    If you're the only person on that machine, there's no point in using safe mode.

    > I am not familiar enough with Linux just yet to know how to give permissions > to my sites to use things such as cron which I desperately need to figure > out. I know how to add a crontab for a user, etc. But when the cron file > runs, I just get a permission denied. I have tried it for both root and the > site user. The only thing that does work is me getting an email stating > permission denied. So I know my crontab file is correct. As far as > permissions, I'm in a cloud. I have no idea what to do to make it work and > maintain a secure system.

    Perhaps you just forgot to make your program/script executable ("chmod +x your_script"). > Anyone know where some great (free) docs that will show me how to fish > around in Linux? I don't need to be hand fed. Just some direction. Thanks!

    Almost all programs have man pages, so you can use "man chmod" to find out about "chmod". And then there's the Linux Documentation Project <http://www.tldp.org/>, which has lots of howtos.

    Regards... Michael

    attached mail follows:


    Thank you. Yes, I did chmod my scripts. chmod 754 and tried 755 too. Don't see why it should be x on the world, though. I would think if the script is being called by its owner, then x on the owner and group should be enough, no?

    I'm even using !#/usr/bin/php ... but then it doesn't even seem to be using it.

    I'll go through the man pages again, too.

    The "find" and "locate" commands will be useful. I will try those. Thanks! Although since you mentioned the local configuration via apache's .htaccess, maybe that is what I need. I still can't figure out how to turn safe mode off for the local column.

    Thanks,

    Nicole

    --
    

    "Michael Mauch" <michael.mauchgmx.de> wrote in message news:69dugxvsi.ln2elmicha.333200002251-0001.dialin.t-online.de... > Nicole <430ntr3kaeontrek.com> wrote: > > I am having trouble doing things with PHP such as use the exec, system, > > etc. functions. I can't seem to find the correct php.ini to turn safe_mode > > off. The one file I did find has safe_mode turned off. When I view phpinfo() > > it shows the global column with safe_mode off, but for the local column, it > > is on. Is there a local php.ini file for each site? > > No. But the values found in the global php.ini can be changed in > Apache's httpd.conf and in .htaccess files. See > <http://www.php.net/manual/en/configuration.changes.php>. > > You can have a .htaccess file in every directory to pass additional > options to Apache (and mod_php). A .htaccess is used for the directory > where it resides and for all subdirectories. > > Try "locate .htaccess" or "find / -name .htaccess". > > > I need to call a script to run in the background and I want to be able to > > use exec() to call it. Is there an alternative way to do this without > > bothering with the safe_mode value? i'd prefer to leave safe_mode on; but at > > the same rate, I am the only one with access to the server as it is my > > dedicated server. > > If you're the only person on that machine, there's no point in using > safe mode. > > > I am not familiar enough with Linux just yet to know how to give permissions > > to my sites to use things such as cron which I desperately need to figure > > out. I know how to add a crontab for a user, etc. But when the cron file > > runs, I just get a permission denied. I have tried it for both root and the > > site user. The only thing that does work is me getting an email stating > > permission denied. So I know my crontab file is correct. As far as > > permissions, I'm in a cloud. I have no idea what to do to make it work and > > maintain a secure system. > > Perhaps you just forgot to make your program/script executable ("chmod > +x your_script"). > > > Anyone know where some great (free) docs that will show me how to fish > > around in Linux? I don't need to be hand fed. Just some direction. Thanks! > > Almost all programs have man pages, so you can use "man chmod" to find > out about "chmod". And then there's the Linux Documentation Project > <http://www.tldp.org/>, which has lots of howtos. > > Regards... > Michael

    attached mail follows:


    correction:

    #!/usr/bin/php

    --
    Nicole
    URLTrak.com
    ElixirSafelist.com
    aeontrek.com
    "Nicole" <430ntr3kaeontrek.com> wrote in message
    news:20030202070736.72896.qmailpb1.pair.com...
    > Thank you. Yes, I did chmod my scripts. chmod 754 and tried 755 too. Don't
    > see why it should be x on the world, though. I would think if the script
    is
    > being called by its owner, then x on the owner and group should be enough,
    > no?
    >
    > I'm even using !#/usr/bin/php ... but then it doesn't even seem to be
    using
    > it.
    >
    > I'll go through the man pages again, too.
    >
    > The "find" and "locate" commands will be useful. I will try those. Thanks!
    > Although since you mentioned the local configuration via apache's
    .htaccess,
    > maybe that is what I need. I still can't figure out how to turn safe mode
    > off for the local column.
    >
    > Thanks,
    >
    > Nicole
    >
    > --
    >
    > "Michael Mauch" <michael.mauchgmx.de> wrote in message
    > news:69dugxvsi.ln2elmicha.333200002251-0001.dialin.t-online.de...
    > > Nicole <430ntr3kaeontrek.com> wrote:
    > > > I am having trouble doing things with PHP such as use the exec,
    system,
    > > > etc. functions. I can't seem to find the correct php.ini to turn
    > safe_mode
    > > > off. The one file I did find has safe_mode turned off. When I view
    > phpinfo()
    > > > it shows the global column with safe_mode off, but for the local
    column,
    > it
    > > > is on. Is there a local php.ini file for each site?
    > >
    > > No. But the values found in the global php.ini can be changed in
    > > Apache's httpd.conf and in .htaccess files. See
    > > <http://www.php.net/manual/en/configuration.changes.php>.
    > >
    > > You can have a .htaccess file in every directory to pass additional
    > > options to Apache (and mod_php). A .htaccess is used for the directory
    > > where it resides and for all subdirectories.
    > >
    > > Try "locate .htaccess" or "find / -name .htaccess".
    > >
    > > > I need to call a script to run in the background and I want to be able
    > to
    > > > use exec() to call it. Is there an alternative way to do this without
    > > > bothering with the safe_mode value? i'd prefer to leave safe_mode on;
    > but at
    > > > the same rate, I am the only one with access to the server as it is my
    > > > dedicated server.
    > >
    > > If you're the only person on that machine, there's no point in using
    > > safe mode.
    > >
    > > > I am not familiar enough with Linux just yet to know how to give
    > permissions
    > > > to my sites to use things such as cron which I desperately need to
    > figure
    > > > out. I know how to add a crontab for a user, etc.  But when the cron
    > file
    > > > runs, I just get a permission denied. I have tried it for both root
    and
    > the
    > > > site user. The only thing that does work is me getting an email
    stating
    > > > permission denied. So I know my crontab file is correct. As far as
    > > > permissions, I'm in a cloud. I have no idea what to do to make it work
    > and
    > > > maintain a secure system.
    > >
    > > Perhaps you just forgot to make your program/script executable ("chmod
    > > +x your_script").
    > >
    > > > Anyone know where some great (free) docs that will show me how to fish
    > > > around in Linux? I don't need to be hand fed. Just some direction.
    > Thanks!
    > >
    > > Almost all programs have man pages, so you can use "man chmod" to find
    > > out about "chmod". And then there's the Linux Documentation Project
    > > <http://www.tldp.org/>, which has lots of howtos.
    > >
    > > Regards...
    > > Michael
    >
    >
    

    attached mail follows:


    Weston Houghton wrote:

    > > All, > > I seem to be getting a silly error on Solaris when trying to do a PHP > 4.3 make. I get an error that looks to me like the liner arguments are > just too long. to be honest, I'm a bit stupified as to why this is > happening or how to fix it. FWIW, I have compiled 4.23 just fine on > that box. > > Thanks, > Wes > > > p.s. here's the last bit of the error: > > /bin/sh libtool --silent --mode=link gcc -export-dynamic -g -O2 > -avoid-version -module -L/usr/ucblib > -L/usr/local/lib/gcc-lib/sparc-sun-solaris2.6/2.8.1 > -L/export/home/oracle/OraHome/lib -R /usr/ucblib -R > /usr/local/lib/gcc-lib/sparc-sun-solaris2.6/2.8.1 -R > /export/home/oracle/OraHome/lib ext/ctype/ctype.lo ext/ftp/php_ftp.lo > ext/ftp/ftp.lo ext/mysql/php_mysql.lo ext/mysql/libmysql/libmysql.lo

    <snip>

    Install GNU sed. The standard Solaris sed can't handle input that long. (I believe it has a character limit of 4096 characters or something to that effect.) GNU's sed doesn't have that limit.

    Installing the package from www.sunfreeware.com will put GNU sed in /usr/local. Make sure that make can find the GNU sed before it finds Sun's sed by putting /usr/local/bin before /usr/bin in your $PATH.

    J

    attached mail follows:


    On Friday, January 31, 2003, at 08:13 PM, Weston Houghton wrote:

    > I seem to be getting a silly error on Solaris when trying to do a PHP > 4.3 make. I get an error that looks to me like the liner arguments are > just too long. to be honest, I'm a bit stupified as to why this is > happening or how to fix it. FWIW, I have compiled 4.23 just fine on > that box.

    I built 4.3.0 on Solaris 2.6 and Solaris 8 without trouble. But as another poster suggested, I am using GNU utils (sed, make, etc).

    attached mail follows:


    I have a PHP script that works on older versions of PHP but on 4.3, it outputs nothing. Here's my code:

    <?php echo '<SCRIPT language="JavaScript" type="text/javascript">'."\n" ."\n".'if (document.location == top.location)'."\n" .' top.location="home.php?goto=' .base64_encode($_SERVER["REQUEST_URI"]).'";'."\n" .'</SCRIPT>'; ?>

    The problem is, when it redirects, the URL variable goto is empty. I'm assuming this has something to do with base64_encode. Since this code snipet is on every page of my site, it'd be a hard hassle to change it so is there a setting in PHP I need to tweak or should I set aside a few hours to edit this code? If the latter, what should I change it to?

    Thanks, Stephen Craton http://www.melchior.us

    "What's the point in appearance if your true love, doesn't care about it?" -- http://www.melchior.us

    attached mail follows:


    What about $_GET['goto']??? Sounds like another register_globals issue. Also, instead of base64 encoding, you may want to use the rawurlencode and rawurldecode functions.

    On Saturday 01 February 2003 07:02 pm, Stephen wrote: > I have a PHP script that works on older versions of PHP but on 4.3, it > outputs nothing. Here's my code: > > <?php > echo '<SCRIPT language="JavaScript" type="text/javascript">'."\n" > ."\n".'if (document.location == top.location)'."\n" > .' top.location="home.php?goto=' > .base64_encode($_SERVER["REQUEST_URI"]).'";'."\n" > .'</SCRIPT>'; > ?> > > The problem is, when it redirects, the URL variable goto is empty. I'm > assuming this has something to do with base64_encode. Since this code > snipet is on every page of my site, it'd be a hard hassle to change it so > is there a setting in PHP I need to tweak or should I set aside a few hours > to edit this code? If the latter, what should I change it to? > > Thanks, > Stephen Craton > http://www.melchior.us > > "What's the point in appearance if your true love, doesn't care about > it?" -- http://www.melchior.us

    -- 
    If anyone can show me, and prove to me, that I am wrong in thought or deed, I 
    will gladly change. I seek the truth, hich never yet hurt anybody. It is only 
    persistence in elf-delusion and ignorance which does harm.
    

    -Marcus Aurelius

    attached mail follows:


    I am displaying a form using values obtained from a database query. One of the elements contains about 20 different values. I want the use to be able to select multiple values before pressing submit.

    This seems to work, but when my php script is called, all I see is the last data value assigned to the variable. I could use a pointer.

    Here is a code snippet:

    echo "<TR>\n"; echo " <TD>Task Description</TD>\n"; echo " <TD><SELECT NAME='in_task_descr' MULTIPLE SIZE=4>\n"; for ($j = 0; $j < $tskcount; $j++) { echo "<OPTION VALUE=\"$taskdescr[$j]\">$taskdescr[$j]</OPTION>\n"; } echo " </SELECT>\n"; echo " </TD>\n"; echo "</TR>\n\n";

    The above code adds a list to the form and the user can highlight more than one entry.

    How do I access the data after the user presses submit?

    -- 
    Jim Kaufman		mailto:jmklinuxforbusiness.net
    Linux Evangelist	cell: 612-481-9778		
    public key 0x6D802619	fax:  952-937-9832
    http://www.linuxforbusiness.net
    

    attached mail follows:


    Put empty square brackets (NAME='in_task_descr[]') after the name of your select element. Then all the slections will be in an array called...

    $_POST['in_task_descr'] or $_GET['in_task_descr']

    Depending on your form method.

    James Kaufman wrote: > I am displaying a form using values obtained from a database query. > One of the elements contains about 20 different values. I want the > use to be able to select multiple values before pressing submit. > > This seems to work, but when my php script is called, all I see is > the last data value assigned to the variable. I could use a pointer. > > Here is a code snippet: > > echo "<TR>\n"; > echo " <TD>Task Description</TD>\n"; > echo " <TD><SELECT NAME='in_task_descr' MULTIPLE SIZE=4>\n"; > for ($j = 0; $j < $tskcount; $j++) { > echo "<OPTION VALUE=\"$taskdescr[$j]\">$taskdescr[$j]</OPTION>\n"; > } > echo " </SELECT>\n"; > echo " </TD>\n"; > echo "</TR>\n\n"; > > The above code adds a list to the form and the user can highlight more than one > entry. > > How do I access the data after the user presses submit? >

    -- 
    By-Tor.com
    It's all about the Rush
    http://www.by-tor.com
    

    attached mail follows:


    Hi,

    Sunday, February 2, 2003, 1:29:30 PM, you wrote: JK> I am displaying a form using values obtained from a database query. JK> One of the elements contains about 20 different values. I want the JK> use to be able to select multiple values before pressing submit.

    JK> This seems to work, but when my php script is called, all I see is JK> the last data value assigned to the variable. I could use a pointer.

    JK> Here is a code snippet:

    JK> echo "<TR>\n"; JK> echo " <TD>Task Description</TD>\n"; JK> echo " <TD><SELECT NAME='in_task_descr' MULTIPLE SIZE=4>\n"; JK> for ($j = 0; $j < $tskcount; $j++) { JK> echo "<OPTION VALUE=\"$taskdescr[$j]\">$taskdescr[$j]</OPTION>\n"; JK> } JK> echo " </SELECT>\n"; JK> echo " </TD>\n"; JK> echo "</TR>\n\n";

    JK> The above code adds a list to the form and the user can highlight more than one JK> entry.

    JK> How do I access the data after the user presses submit?

    JK> -- JK> Jim Kaufman mailto:jmklinuxforbusiness.net JK> Linux Evangelist cell: 612-481-9778 JK> public key 0x6D802619 fax: 952-937-9832 JK> http://www.linuxforbusiness.net

    This popped up using google http://www.onlinetools.org/tricks/using_multiple_select.php

    -- 
    regards,
    Tom
    

    attached mail follows:


    PHP keeps track of what line# is being executed, so that when there's an error (say in pg_exec() ) it reports what line the error occured on.

    This appears to happen even during runtime (not just during compilation).

    For example: ------------------------- <? $dbname="mydb"; $dbuser="myuser"; $dbpass="mypw";

    $conn=pg_connect("dbname=$dbname, user=$dbuser, password=$dbpass"); $cmd="go and ask the mice"; $result=pg_exec($conn, $cmd); ?> --------------------------

    This would result in a pg_exec error ~ line 7. PHP tracks this, even though the error is during runtime, not during the precompile.

    Is there a function where I can access this information? Something like "get_line();" or something?

    This would be REALLY HANDY for debugging large projects...

    -Ben

    attached mail follows:


    I think what you are looking for is: __LINE__

    See: http://www.php.net/manual/en/language.constants.predefined.php

    Cheers, Steven Balthazor

    -----Original Message----- From: Benjamin Smith [mailto:benseffortlessis.com] Sent: Saturday, February 01, 2003 8:59 PM To: php-generallists.php.net Subject: [PHP] Line Number function?

    PHP keeps track of what line# is being executed, so that when there's an error (say in pg_exec() ) it reports what line the error occured on.

    This appears to happen even during runtime (not just during compilation).

    For example: ------------------------- <? $dbname="mydb"; $dbuser="myuser"; $dbpass="mypw";

    $conn=pg_connect("dbname=$dbname, user=$dbuser, password=$dbpass"); $cmd="go and ask the mice"; $result=pg_exec($conn, $cmd); ?> --------------------------

    This would result in a pg_exec error ~ line 7. PHP tracks this, even though the error is during runtime, not during the precompile.

    Is there a function where I can access this information? Something like "get_line();" or something?

    This would be REALLY HANDY for debugging large projects...

    -Ben

    -- 
    PHP General Mailing List (http://www.php.net/)
    To unsubscribe, visit: http://www.php.net/unsub.php
    

    attached mail follows:


    On Sat, 1 Feb 2003 19:59:00 -0800, you wrote:

    >PHP keeps track of what line# is being executed, so that when there's an >error (say in pg_exec() ) it reports what line the error occured on. [...] >Is there a function where I can access this information? Something like >"get_line();" or something?

    Do you mean like the predefined "constant" __LINE__?

    http://www.php.net/manual/en/language.constants.predefined.php

    Sorry if I'm misunderstanding the question...

    attached mail follows:


    On Sun, 2 Feb 2003, Michael Sims wrote:

    > On Sat, 1 Feb 2003 19:59:00 -0800, you wrote: > > >PHP keeps track of what line# is being executed, so that when there's an > >error (say in pg_exec() ) it reports what line the error occured on. > [...] > >Is there a function where I can access this information? Something like > >"get_line();" or something? > > Do you mean like the predefined "constant" __LINE__? > > http://www.php.net/manual/en/language.constants.predefined.php

    Yep, that will do it and has been available in PHP for a very long time (along with __FILE__). PHP 4.3.0 introduces the following:

    __FUNCTION__ Function name __CLASS__ Class name debug_backtrace() Debugging information including the line number

    See: http://www.php.net/debug_backtrace

    Regards, Philip

    attached mail follows:


    Is it possible (using an apache directive, perhaps?) to turn off php parsing for certain directories within a site? (but not others?)

    I picture something like (in httpd.conf)

    <directory /home/www/somesite.com/codearchive> AllowOverride All Options FollowSymLinks NoParsePHP </directory>

    Can this be done? How? Perhaps as a php_value entry in the <VirtualHost> directive?

    Thanks,

    -Ben

    attached mail follows:


    If you don't use <?php tags in the file it won't make a huge different if it is on or off... but if you don't want any parsing see below.

    In your .htaccess file do the following for the file types to be turned off and remember that this will be from here out in the doc tree:

    AddType text/html .html .php

    Timothy Hitchens (HiTCHO) Web Application Consulting e-mail: timhitcho.com.au

    > -----Original Message----- > From: Benjamin Smith [mailto:benseffortlessis.com] > Sent: Sunday, 2 February 2003 3:32 PM > To: php-generallists.php.net > Subject: [PHP] Turn off PHP for certain directories? > > > Is it possible (using an apache directive, perhaps?) to turn > off php parsing > for certain directories within a site? (but not others?) > > I picture something like (in httpd.conf) > > <directory /home/www/somesite.com/codearchive> > AllowOverride All > Options FollowSymLinks > NoParsePHP > </directory> > > Can this be done? How? Perhaps as a php_value entry in the > <VirtualHost> > directive? > > Thanks, > > -Ben > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >

    attached mail follows:


    Hi,

    Sunday, February 2, 2003, 3:32:28 PM, you wrote: BS> Is it possible (using an apache directive, perhaps?) to turn off php parsing BS> for certain directories within a site? (but not others?)

    BS> I picture something like (in httpd.conf)

    BS> <directory /home/www/somesite.com/codearchive> BS> AllowOverride All BS> Options FollowSymLinks BS> NoParsePHP BS> </directory>

    BS> Can this be done? How? Perhaps as a php_value entry in the <VirtualHost> BS> directive?

    BS> Thanks,

    BS> -Ben

    you could try

    php_flag engine = Off

    -- 
    regards,
    Tom
    

    attached mail follows:


    At 12:25 02.02.2003, Tom Rogers said: --------------------[snip]-------------------- >you could try > >php_flag engine = Off --------------------[snip]--------------------

    I've tried (this works): In the configuration for the virtual host: AllowOverride All

    In .htaccess: AddType text/plain .php

    engine=off returns an apache config error.

    -- 
       >O     Ernest E. Vogelsinger
       (\)    ICQ #13394035
        ^     http://www.vogelsinger.at/
    

    attached mail follows:


    Howdy ...

    I've just installed php, zend developer, mysqladmin, and apache on my pc laptop.

    Are there any available for mac 8.6 ?

    cheers,

    bobbi-lea

    ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ CyberFaerie media :: entertainment

    m:: 0411 543 554 e:: bobbi-leacyberfaerie.com a:: 32 acland dr, strathpine, qld 4500 ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

    This email and any files transmitted with it are confidential and intended solely for the use of the individual or entity to which they are addressed. If you have received this e-mail in error you are prohibited from disclosing, copying or using the information contained in it. If you have received this email in error, please inform us by email reply and delete the message and attached documents. This footnote also confirms that this email message has been swept for the presence of computer viruses.

    attached mail follows:


    If you are referring to php etc NO and for Zend NO.

    Timothy Hitchens (HiTCHO) Web Application Consulting e-mail: timhitcho.com.au

    > -----Original Message----- > From: Bobbi-Lea [mailto:bobbi-leacyberfaerie.com] > Sent: Sunday, 2 February 2003 2:30 PM > To: php-generallists.php.net > Subject: [PHP] php and Mac running 8.6 > > > Howdy ... > > I've just installed php, zend developer, mysqladmin, and > apache on my pc laptop. > > Are there any available for mac 8.6 ? > > cheers, > > bobbi-lea > > > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ > CyberFaerie > media :: entertainment > > m:: 0411 543 554 > e:: bobbi-leacyberfaerie.com > a:: 32 acland dr, strathpine, qld 4500 > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ > > This email and any files transmitted with it are confidential > and intended solely for the use of the individual or entity > to which they are addressed. If you have received this e-mail > in error you are prohibited from disclosing, copying or using > the information contained in it. If you have received this > email in error, please inform us by email reply and delete > the message and attached documents. This footnote also > confirms that this email message has been swept for the > presence of computer viruses. > >

    attached mail follows:


    on 02/02/03 3:30 PM, Bobbi-Lea (bobbi-leacyberfaerie.com) wrote:

    > I've just installed php, zend developer, mysqladmin, and apache on my pc > laptop. > > Are there any available for mac 8.6 ?

    Not to the best of my knowledge... mac OSX has though :)

    Justin

    attached mail follows:


    Hello guys and gals!!! can you tell me why i can't get this script to print my table.... thanks Karl please check out the code below obviously i left my username and passwords blank :-) ----------------------------------------------------------------------------- -------------------------------------------------------- <? $sqlhost = "localhost"; $sqllogin = "login"; $sqlpw = "password"; $sqldb = "database table name"; (!mysql_pconnect($sql[localhost], $sql[wedbd13], $sql[webdb13])) { die(mysql_error()); } (!mysql_select_db($sql[wedbd13])) { die(mysql_error()); } $result = mysql_query("SELECT * FROM `assignment_one`"); while($array = mysql_fetch_array($result)) { echo("| %s | %s | %s | %s | %s |<br />", $array[id], $array[username], $array[password], $array[status], $array[notes]); } ?> -------------------------------------------------------------------------------------------------------------------------------------

    attached mail follows:


    echo("| %s | %s | %s | %s | %s |<br />", $array[id], $array[username], $array[password], $array[status], $array[notes]);

    try echo "| %s | %s | %s | %s | %s |<br />".$array[id]." ".$array[username]." ".$array[password]." ".$array[status]." ".$array[notes];

    dots not comas between variables. Hope this helps. Hugh ----- Original Message ----- From: "Karl James" <karl.jamesverizon.net> To: "php" <php-generallists.php.net> Sent: Friday, January 31, 2003 10:37 PM Subject: [PHP] help with script!!!

    Hello guys and gals!!!

    can you tell me why i can't get this script to print my table....

    thanks Karl

    please check out the code below obviously i left my username and passwords blank :-)

    ---------------------------------------------------------------------------- - -------------------------------------------------------- <? $sqlhost = "localhost"; $sqllogin = "login"; $sqlpw = "password"; $sqldb = "database table name"; (!mysql_pconnect($sql[localhost], $sql[wedbd13], $sql[webdb13])) { die(mysql_error()); } (!mysql_select_db($sql[wedbd13])) { die(mysql_error()); } $result = mysql_query("SELECT * FROM `assignment_one`"); while($array = mysql_fetch_array($result)) { echo("| %s | %s | %s | %s | %s |<br />", $array[id], $array[username], $array[password], $array[status], $array[notes]); } ?> ---------------------------------------------------------------------------- ---------------------------------------------------------

    --
    PHP General Mailing List (http://www.php.net/)
    To unsubscribe, visit: http://www.php.net/unsub.php
    

    attached mail follows:


    On Sat, 1 Feb 2003, Karl James wrote:

    > Hello guys and gals!!! > > can you tell me why i can't get this script to print my > table.... > > thanks Karl > > please check out the code below > obviously i left my username and passwords blank :-) > > > ----------------------------------------------------------------------------- > -------------------------------------------------------- > <? > $sqlhost = "localhost"; > $sqllogin = "login"; > $sqlpw = "password"; > $sqldb = "database table name"; > (!mysql_pconnect($sql[localhost], $sql[wedbd13], $sql[webdb13])) { > die(mysql_error()); } > (!mysql_select_db($sql[wedbd13])) { die(mysql_error()); } > $result = mysql_query("SELECT * FROM `assignment_one`"); > while($array = mysql_fetch_array($result)) { > echo("| %s | %s | %s | %s | %s |<br />", $array[id], $array[username], > $array[password], $array[status], $array[notes]); > } > ?>

    Maybe this will help:

    <?php if (!mysql_connect($host, $user, $pass)) { echo "Could not connect to MySQL"; exit; } if (!mysql_select_db($dbname)) { echo "Could not select database ($dbname) : " . mysql_error(); exit; }

    $sql = "SELECT id,username,password,status,notes FROM assignment_one"; $result = mysql_query($sql);

    if (!$result) { echo "Could not run query ($sql) : " . mysql_error(); exit; }

    while ($row = mysql_fetch_assoc($result)) { extract($row);

    echo "| $id | $username | $password | $status | $notes |<br />\n"; } ?>

    Regards, Philip

    attached mail follows:


    > echo("| %s | %s | %s | %s | %s |<br />", $array[id], > $array[username], > $array[password], $array[status], $array[notes]);

    If you look at http://www.php.net/echo you'll see that echo does not support this syntax. If you want to use this syntax then you should probably be using some form of printf (see http://www.php.net/printf).

    CYA, Dave

    attached mail follows:


    On Sat, 1 Feb 2003, Hugh Danaher wrote:

    > echo("| %s | %s | %s | %s | %s |<br />", $array[id], $array[username], > $array[password], $array[status], $array[notes]); > > try > echo "| %s | %s | %s | %s | %s |<br />".$array[id]." ".$array[username]." > ".$array[password]." ".$array[status]." ".$array[notes]; > > dots not comas between variables.

    echo takes on commas as we can echo multiple variables which isn't something we can do with print. This is also the main difference between echo and print. So, the commas are okay here but as someone else already stated, echo doesn't behave like printf so no special %formatting% with echo.

    Regards, Philip

    attached mail follows:


    hey guys when you send me attachment, It wont let me view the .dat file what is that? I tried to open with notepad and dreamweaver but it wont view the code. Karl

    attached mail follows:


    I will be quick.

    if . matches any character except newline (by default) then what can i use to match any character INCLUDING newline?

    attached mail follows:


    Thank you chris,

    Help full

    Do you have any link for installation manual

    "Chris Hayes" <chayesantenna.nl> wrote in message news:5.1.1.6.0.20030201222741.01815238pop4.antenna.nl... > At 21:36 1-2-2003, you wrote: > > > I am studying on php. And the book say, when the server see php > > extension it > > > is running php file and giving results to the visiting browser. > > > > > > But as I see related directories are normal directory, doesn' t like > > cgi-bin > > > directories. > > > > > > Is there any change to see php file source such as file open function or > > > something else? I am not going to somebody else file. Just I want to be > > sure > > > how secure the php? > > > >It's all in CVS, read the source: > > I think he does not mean the PHP program source, but his scripts' source. > > Normally people cannot see the script source, as long as you use .php as > file extension. In some PHP/server setups people can see the source when > they type filename.phps, see the installation instruction file in the php > package for details. > >

    attached mail follows:


    See www.php.net.

    Qt wrote: > Thank you chris, > > Help full > > Do you have any link for installation manual > > > "Chris Hayes" <chayesantenna.nl> wrote in message > news:5.1.1.6.0.20030201222741.01815238pop4.antenna.nl... > >>At 21:36 1-2-2003, you wrote: >> >>>>I am studying on php. And the book say, when the server see php >>> >>>extension it >>> >>>>is running php file and giving results to the visiting browser. >>>> >>>>But as I see related directories are normal directory, doesn' t like >>> >>>cgi-bin >>> >>>>directories. >>>> >>>>Is there any change to see php file source such as file open function >>> > or > >>>>something else? I am not going to somebody else file. Just I want to >>> > be > >>>sure >>> >>>>how secure the php? >>> >>>It's all in CVS, read the source: >> >>I think he does not mean the PHP program source, but his scripts' source. >> >>Normally people cannot see the script source, as long as you use .php as >>file extension. In some PHP/server setups people can see the source when >>they type filename.phps, see the installation instruction file in the php >>package for details. >> >> > > >

    attached mail follows:


    I am trying to load a php script to run in the background using the exec() function. My code looks like this:

    <? // ....

    $aqid = $db->insert_id(); //grab id of newly inserted row $cmd = "php -q sendit.php $aqid >/dev/null 2>&1 &"; exec("$cmd"); // call sendit.php in background // ... ?>

    Basically, the point of me doing this is so the script runs in the background so the member does not have to wait for the script to run after they have clicked a send button. But they are still waiting because they can't go to other pages until the script has completed running.

    My next alternative will be to run a cron job to do this instead. But I can't get cron working just yet. Any suggestions to get the script to run in background without stalling the script that calls it?

    --
    Nicole
    

    attached mail follows:


    Don't get your question right, but you get all your vars in the querystring after submitting the form. There, you should check on whether or not the var is filled (i.e. $var <> "" or so). There's no other way :-( so your guess is pretty ok.

    BTW: use Javascript to modify the submitted values.

    Edwin

    Anders Thoresson wrote: > Hi, > > I've got a html form where not all fields need to be filled by the > users. How can I build a MySQL query based on which fields the user have > filled? > > My guess is that I can do something like this: > > if(!empty($f_name)) { > some_commands_to_add_$f_name_to_querystring > } > if(!empty($l_name)) { > some_commands_to_add_$f_name_to_querystring > } > some_commands_to_build_querystring_based_on_if's > > $result = mysql_query($query) > > > But what commands/functions should I use to build the query? >

    attached mail follows:


    Helloo people,

    I have to build a database abstraction class with support for XML output. My XML output has to look like this:

    <?xml version="1.0" ?> <result query="SELECT * FROM books"> <row number="1"> <field name="name">value</field> <field name="name">value</field> ... </row> <row number="2"> <field name="name">value</field> <field name="name">value</field> ... </row> .... .... </result>

    Well i almost got it, but how do i get all the field names of my MySQL tables? This is my code, a part of my database class. :

    /**

    * getXMLDocument

    *

    * Get the result of your query back in XML document

    * author Davy Obdam

    */

    function getXMLDocument() {

    //Create XML document

    if(!$this->xmlDoc = domxml_new_doc("1.0")) {

    die("[ERROR] Cant create XML document");

    }

    // Create root element

    $this->root_element = $this->xmlDoc->create_element("result");

    $this->root_element->set_attribute("query", $this->sqlQuery);

    //Get database fields and values

    $count = 0;

    while($this->fetchRow()) {

    $row_element = $this->xmlDoc->create_element("row");

    $n_row = $this->root_element->append_child($row_element);

    $row_number = $row_element->set_attribute("number" ,$count);

    $count++;

    // Get fieldnames and values

    for($i=0; $i<sizeof($this->sqlQuery); $i++) {

    $field_element = $this->xmlDoc->create_element("field");

    $n_field = $row_element->append_child($field_element);

    $field_name = $field_element->set_attribute("name", "name");

    $field_content = $field_element->append_child($this->xmlDoc->create_text_node(utf8_encode("text")));

    }

    $this->moveNext();

    }

    // Put everything together and show it

    $append_root = $this->xmlDoc->append_child($this->root_element);

    header("content-type:text/xml");

    echo $this->xmlDoc->dump_mem();

    }

    Now all i get is one field <field name="name">whatever</field> in my XML output, but i should get 10 with this particular query.. Any help is appreciated, thanks for you time.

    Best regards,

    Davy Obdam mailto:infodavyobdam.com

    attached mail follows:


    Hi,

    I building a form which will be used to set access rights to different parts of my web album. When editing the settings for each album, like the albums name and wether or not everyone should be allowed to upload pictures to it, I also present a list of checkboxes to the administrators. One checkbox for each registred user. If checked, to user is allowed to view the pictures, if not check, no pictures show.

    The checkbox part of the form I build uses this code:

    db_connect($dbuser, $dbpassword, $dbdatabase); $query = "SELECT userid FROM members"; $result = mysql_query($query); while($row = mysql_fetch_array($result)) { echo($row[0]); ?> <INPUT TYPE="checkbox" name="<?php echo($row[0])?>" VALUE="YES">

    But how do I process this form when saving the settings for the album? For the forms I've built so far, I've known what information I can find in $_REQUEST['']. But this time, I don't know how many checkboxes there are, and what their names will be. How do I do this?

    Is the form ok, or is a bad form design the reason I can't figure out what to form processing code should be?

    -- 
    anders thoresson
    

    attached mail follows:


    howabout making the checkboxes an array i.e. <INPUT TYPE="checkbox" name="checkbox[<?php echo($row[0])?>]" VALUE="YES">

    then when processing ... foreach($_REQUEST["checkbox"] as $checkbox) { ... }

    Tim Ward http://www.chessish.com mailto:timwardchessish.com ----- Original Message ----- From: anders thoresson <listorthoresson.net> To: <php-generallists.php.net> Sent: Sunday, February 02, 2003 12:28 PM Subject: [PHP] processing form with unknown number of checkboxes, each with a unknown name.

    > Hi, > > I building a form which will be used to set access rights to different > parts of my web album. When editing the settings for each album, like the > albums name and wether or not everyone should be allowed to upload pictures > to it, I also present a list of checkboxes to the administrators. One > checkbox for each registred user. If checked, to user is allowed to view > the pictures, if not check, no pictures show. > > The checkbox part of the form I build uses this code: > > db_connect($dbuser, $dbpassword, $dbdatabase); > $query = "SELECT userid FROM members"; > $result = mysql_query($query); > while($row = mysql_fetch_array($result)) { > echo($row[0]); > ?> > <INPUT TYPE="checkbox" name="<?php echo($row[0])?>" VALUE="YES"> > > > But how do I process this form when saving the settings for the album? For > the forms I've built so far, I've known what information I can find in > $_REQUEST['']. But this time, I don't know how many checkboxes there are, > and what their names will be. How do I do this? > > Is the form ok, or is a bad form design the reason I can't figure out what > to form processing code should be? > > -- > anders thoresson > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >