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Neohapsis > Archives > PHP Discussion Digest> 2005-08

php-general Digest 7 Aug 2005 12:58:29 -0000 Issue 3611

php-general-digest-helplists.php.net
Date: Sun Aug 07 2005 - 07:58:29 CDT

Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]

php-general Digest 7 Aug 2005 12:58:29 -0000 Issue 3611

Topics (messages 220151 through 220169):

Re: sorry for asking here,a small apache query
220151 by: Alan Milnes

Fast count of recordset in php...
        220152 by: Gustav Wiberg
        220153 by: Matt Darby
        220155 by: Sebastian
        220164 by: TalkativeDoggy
        220165 by: TalkativeDoggy
        220168 by: Gustav Wiberg

Re: [PHP-DEV] Re: [PHP] Exceptions: function x throws Exception
220154 by: Marcus Boerger
220159 by: Jochem Maas

Re: PHP 5.0.4 on AMD64
220156 by: Joseph Oaks

PHP 4.3.9 - Undefined variable: authed in
220157 by: Trevor Tregoweth
220158 by: Jochem Maas

Re: varibles defination
220160 by: Jochem Maas

Re: Average time spent on a page
220161 by: M Saleh EG

mkdir, Shared Hosting?
        220162 by: Esteamedpw.aol.com
        220163 by: Robbert van Andel
        220166 by: Esteamedpw.aol.com
        220167 by: Burhan Khalid

Re: Java - toString() <-> php - ?
220169 by: Rory Browne

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----------------------------------------------------------------------

attached mail follows:

babu wrote:

>Hi all,
>
>I am sorry for asking in php forum.i am subscribed to php and not to apache.but i hope many people in this group also the solution to this query.
>
If you know you are in wrong place why ask here?

Alan

attached mail follows:

Hello there!

How do i get a fast count of a recordset in php?

Look at this code:

$sql = "SELECT COUNT(IDVara) cn FROM tbvara WHERE Varunamn LIKE
'$checkLev%'";
$querys = mysql_query($sql);

    //Count products in db
    //
    $dbArray = mysql_fetch_array($querys);
    $nrOfProducts = $dbArray["cn"];

It's slow... Why? Any suggestions?

/mr G
varupiraten.se

attached mail follows:

$num=mysql_num_rows($sql);

Gustav Wiberg wrote:

> Hello there!
>
> How do i get a fast count of a recordset in php?
>
> Look at this code:
>
> $sql = "SELECT COUNT(IDVara) cn FROM tbvara WHERE Varunamn LIKE
> '$checkLev%'";
> $querys = mysql_query($sql);
>
> //Count products in db
> //
> $dbArray = mysql_fetch_array($querys);
> $nrOfProducts = $dbArray["cn"];
>
>
> It's slow... Why? Any suggestions?
>
> /mr G
> varupiraten.se
>

attached mail follows:

you'd be suprized how fast an index can be.. you should read the manual
on indexes,
http://dev.mysql.com/doc/mysql/en/mysql-indexes.html

"If a table has 1,000 rows, this is at least 100 times faster than
reading sequentially"

while you may not get 100x faster, it will be faster than having no
index.. also try using mysql_num_rows()

$sql = mysql_query("SELECT col FROM tbvara WHERE Varunamn LIKE
'$checkLev%'");
// record count
echo mysql_num_rows($sql);

PS, 'reply all' to list.

Gustav Wiberg wrote:

> Hi there!
>
> There are about 300 records.
> You're right, I can add an index, but Is that the only way to get a
> faster solution?
>
> /mr G
> varupiraten.se
>
> ----- Original Message ----- From: "Sebastian"
> <sebastianbroadbandgaming.net>
> To: "Gustav Wiberg" <gustavvarupiraten.se>
> Sent: Saturday, August 06, 2005 11:08 PM
> Subject: Re: [PHP] Fast count of recordset in php...
>
>
>> how many records in the table? its going to be slow no matter what,
>> especially if you have a lot of records.. your searching each record
>> then counting them.. do you have any indexes? judging by your query
>> you can add index on Varunamn and it should be more speedy..
>>
>> Gustav Wiberg wrote:
>>
>>> Hello there!
>>>
>>> How do i get a fast count of a recordset in php?
>>>
>>> Look at this code:
>>>
>>> $sql = "SELECT COUNT(IDVara) cn FROM tbvara WHERE Varunamn LIKE
>>> '$checkLev%'";
>>> $querys = mysql_query($sql);
>>>
>>> //Count products in db
>>> //
>>> $dbArray = mysql_fetch_array($querys);
>>> $nrOfProducts = $dbArray["cn"];
>>>
>>>
>>> It's slow... Why? Any suggestions?
>>>
>>> /mr G
>>> varupiraten.se
>>>
>>
>>
>> --
>> No virus found in this outgoing message.
>> Checked by AVG Anti-Virus.
>> Version: 7.0.338 / Virus Database: 267.10.1/64 - Release Date: 8/4/2005
>>
>>
>>
>> --
>> No virus found in this incoming message.
>> Checked by AVG Anti-Virus.
>> Version: 7.0.338 / Virus Database: 267.10.0/63 - Release Date:
>> 2005-08-03
>>
>>
>
>
>
>

--
No virus found in this outgoing message.
Checked by AVG Anti-Virus.
Version: 7.0.338 / Virus Database: 267.10.1/64 - Release Date: 8/4/2005

attached mail follows:

if you just wana get count of recordset,
don't do this:
$sql = mysql_query("SELECT col FROM tbvara WHERE Varunamn LIKE
'$checkLev%'");
// record count
echo mysql_num_rows($sql);

be coz this way is slow and costs more overload.

$sql = "SELECT COUNT(IDVara) cn FROM tbvara WHERE Varunamn LIKE
'$checkLev%'";
$querys = mysql_query($sql);

    //Count products in db
    //
    $dbArray = mysql_fetch_row($querys);
    $nrOfProducts = $dbArray[0];

Sebastian wrote:
> you'd be suprized how fast an index can be.. you should read the manual
> on indexes,
> http://dev.mysql.com/doc/mysql/en/mysql-indexes.html
>
> "If a table has 1,000 rows, this is at least 100 times faster than
> reading sequentially"
>
> while you may not get 100x faster, it will be faster than having no
> index.. also try using mysql_num_rows()
>
> $sql = mysql_query("SELECT col FROM tbvara WHERE Varunamn LIKE
> '$checkLev%'");
> // record count
> echo mysql_num_rows($sql);
>
>
> PS, 'reply all' to list.
>
> Gustav Wiberg wrote:
>
>> Hi there!
>>
>> There are about 300 records.
>> You're right, I can add an index, but Is that the only way to get a
>> faster solution?
>>
>> /mr G
>> varupiraten.se
>>
>> ----- Original Message ----- From: "Sebastian"
>> <sebastianbroadbandgaming.net>
>> To: "Gustav Wiberg" <gustavvarupiraten.se>
>> Sent: Saturday, August 06, 2005 11:08 PM
>> Subject: Re: [PHP] Fast count of recordset in php...
>>
>>
>>> how many records in the table? its going to be slow no matter what,
>>> especially if you have a lot of records.. your searching each record
>>> then counting them.. do you have any indexes? judging by your query
>>> you can add index on Varunamn and it should be more speedy..
>>>
>>> Gustav Wiberg wrote:
>>>
>>>> Hello there!
>>>>
>>>> How do i get a fast count of a recordset in php?
>>>>
>>>> Look at this code:
>>>>
>>>> $sql = "SELECT COUNT(IDVara) cn FROM tbvara WHERE Varunamn LIKE
>>>> '$checkLev%'";
>>>> $querys = mysql_query($sql);
>>>>
>>>> //Count products in db
>>>> //
>>>> $dbArray = mysql_fetch_array($querys);
>>>> $nrOfProducts = $dbArray["cn"];
>>>>
>>>>
>>>> It's slow... Why? Any suggestions?
>>>>
>>>> /mr G
>>>> varupiraten.se

attached mail follows:

if you just wana get count of recordset,
don't do this:
$sql = mysql_query("SELECT col FROM tbvara WHERE Varunamn LIKE
'$checkLev%'");
// record count
echo mysql_num_rows($sql);

be coz this way is slow and costs more overload.

$sql = "SELECT COUNT(IDVara) cn FROM tbvara WHERE Varunamn LIKE
'$checkLev%'";
$querys = mysql_query($sql);

    //Count products in db
    //
    $dbArray = mysql_fetch_row($querys);
    $nrOfProducts = $dbArray[0];

attached mail follows:

Hi again!

Thanx!!! I think this will help a lot!!!

/mr G
varupiraten.se

----- Original Message -----
From: "TalkativeDoggy" <talkativedoggygmail.com>
To: "Sebastian" <sebastianbroadbandgaming.net>
Cc: "Gustav Wiberg" <gustavvarupiraten.se>; <php-generallists.php.net>
Sent: Sunday, August 07, 2005 6:04 AM
Subject: Re: [PHP] Fast count of recordset in php...

> if you just wana get count of recordset,
> don't do this:
> $sql = mysql_query("SELECT col FROM tbvara WHERE Varunamn LIKE
> '$checkLev%'");
> // record count
> echo mysql_num_rows($sql);
>
> be coz this way is slow and costs more overload.
>
> $sql = "SELECT COUNT(IDVara) cn FROM tbvara WHERE Varunamn LIKE
> '$checkLev%'";
> $querys = mysql_query($sql);
>
> //Count products in db
> //
> $dbArray = mysql_fetch_row($querys);
> $nrOfProducts = $dbArray[0];
>
> Sebastian wrote:
>> you'd be suprized how fast an index can be.. you should read the manual
>> on indexes,
>> http://dev.mysql.com/doc/mysql/en/mysql-indexes.html
>>
>> "If a table has 1,000 rows, this is at least 100 times faster than
>> reading sequentially"
>>
>> while you may not get 100x faster, it will be faster than having no
>> index.. also try using mysql_num_rows()
>>
>> $sql = mysql_query("SELECT col FROM tbvara WHERE Varunamn LIKE
>> '$checkLev%'");
>> // record count
>> echo mysql_num_rows($sql);
>>
>>
>> PS, 'reply all' to list.
>>
>> Gustav Wiberg wrote:
>>
>>> Hi there!
>>>
>>> There are about 300 records.
>>> You're right, I can add an index, but Is that the only way to get a
>>> faster solution?
>>>
>>> /mr G
>>> varupiraten.se
>>>
>>> ----- Original Message ----- From: "Sebastian"
>>> <sebastianbroadbandgaming.net>
>>> To: "Gustav Wiberg" <gustavvarupiraten.se>
>>> Sent: Saturday, August 06, 2005 11:08 PM
>>> Subject: Re: [PHP] Fast count of recordset in php...
>>>
>>>
>>>> how many records in the table? its going to be slow no matter what,
>>>> especially if you have a lot of records.. your searching each record
>>>> then counting them.. do you have any indexes? judging by your query
>>>> you can add index on Varunamn and it should be more speedy..
>>>>
>>>> Gustav Wiberg wrote:
>>>>
>>>>> Hello there!
>>>>>
>>>>> How do i get a fast count of a recordset in php?
>>>>>
>>>>> Look at this code:
>>>>>
>>>>> $sql = "SELECT COUNT(IDVara) cn FROM tbvara WHERE Varunamn LIKE
>>>>> '$checkLev%'";
>>>>> $querys = mysql_query($sql);
>>>>>
>>>>> //Count products in db
>>>>> //
>>>>> $dbArray = mysql_fetch_array($querys);
>>>>> $nrOfProducts = $dbArray["cn"];
>>>>>
>>>>>
>>>>> It's slow... Why? Any suggestions?
>>>>>
>>>>> /mr G
>>>>> varupiraten.se
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
>
> --
> No virus found in this incoming message.
> Checked by AVG Anti-Virus.
> Version: 7.0.338 / Virus Database: 267.10.0/63 - Release Date: 2005-08-03
>
>

attached mail follows:

Hello Jochem,

lookup the archieves. We have long ago decided agains that.

marcus

Friday, August 5, 2005, 2:26:04 PM, you wrote:

> Dear Internals,

> class FooBar { public function foo() throws Exception {} }
> function fooFoo() throws Exception {}

> this came up on php-generals and I wondered if anyone had time/cared
> to comment if it (as it does to me) seems like a good idea and/or whether it is
> technically feasable. My thinking was that one could then use the reflection API
> to determine whether functions/methods are capable of throwing exceptions and or
> what kind - might be quite handy when using third party apps/classes
> (PEAR springs to mind.)

> thanks and regards,
> Jochem

> <the rest is blabla aimed at php-generals>

> Torgny Bjers wrote:
>> Norbert Wenzel wrote:
>>
>>>If there is a class with a function, that might throw exceptions and
>>>does NOT catch them, may I write that like in Java?
>>>
>>>class FooClass {
>>>
>>> public function foo() throws Exception {

> think about this, especially in terms of the Reflection API, it sounds
> like a really good idea (at least to me)

>>>
>>> }
>>>
>>>}
>>>
>>>Or is there another possibility to tell a function throws an exception
>>>and to force the caller to handle that exception?
>>>
>>>thanks in advance,
>>>
>>>Norbert
>>>
>>
>>
>> Hello Norbert,
>>
>> The Java way doesn't work here. The best approach would be to simply run
>> a try/catch/finally around the call to your function/method, and inside
>> the function itself you do the following:
>>
>> if (...) { throw new Exception("My message."); } }
>>

> indeed - bottom line is you have to know that a function/method/extension may
> throw. mostly you do know because:

> 1. you wrote the code,
> 2. or it's documented in the extension manual pages
> 3. and/ro you hit an unacaught exception whilst developing.

> my approach to cover any oversights is to wrap every thing in a main try/catch block
> just in case - keeping in mind that the idea is that this 'main' catch block is never run
> is al goes well.

>> Regards,
>> Torgny
>>

Best regards,
Marcus

attached mail follows:

Marcus Boerger wrote:
> Hello Jochem,
>
> lookup the archieves. We have long ago decided agains that.

I'll take your word on it. :-) (shame on me for not searching harder
before asking)

thanks for replying.

>
> marcus
>
> Friday, August 5, 2005, 2:26:04 PM, you wrote:
>
>
>>Dear Internals,
>
>
>>class FooBar { public function foo() throws Exception {} }
>>function fooFoo() throws Exception {}
>
>
>> this came up on php-generals and I wondered if anyone had time/cared
>>to comment if it (as it does to me) seems like a good idea and/or whether it is
>>technically feasable. My thinking was that one could then use the reflection API
>>to determine whether functions/methods are capable of throwing exceptions and or
>>what kind - might be quite handy when using third party apps/classes
>>(PEAR springs to mind.)
>
>
>>thanks and regards,
>>Jochem
>
>
>
>><the rest is blabla aimed at php-generals>
>
>
>>Torgny Bjers wrote:
>>
>>>Norbert Wenzel wrote:
>>>
>>>
>>>>If there is a class with a function, that might throw exceptions and
>>>>does NOT catch them, may I write that like in Java?
>>>>
>>>>class FooClass {
>>>>
>>>> public function foo() throws Exception {
>
>
>>think about this, especially in terms of the Reflection API, it sounds
>>like a really good idea (at least to me)
>
>
>>>> }
>>>>
>>>>}
>>>>
>>>>Or is there another possibility to tell a function throws an exception
>>>>and to force the caller to handle that exception?
>>>>
>>>>thanks in advance,
>>>>
>>>>Norbert
>>>>
>>>
>>>
>>>Hello Norbert,
>>>
>>>The Java way doesn't work here. The best approach would be to simply run
>>>a try/catch/finally around the call to your function/method, and inside
>>>the function itself you do the following:
>>>
>>>if (...) { throw new Exception("My message."); } }
>>>
>
>
>>indeed - bottom line is you have to know that a function/method/extension may
>>throw. mostly you do know because:
>
>
>>1. you wrote the code,
>>2. or it's documented in the extension manual pages
>>3. and/ro you hit an unacaught exception whilst developing.
>
>
>>my approach to cover any oversights is to wrap every thing in a main try/catch block
>>just in case - keeping in mind that the idea is that this 'main' catch block is never run
>>is al goes well.
>
>
>>>Regards,
>>>Torgny
>>>
>
>
>
>
>
> Best regards,
> Marcus
>

attached mail follows:

that chcon did the trick, thanks.

Joe

Joseph Oaks (trelltrells.com) wrote:
>
> Thanks, I will give that a try, and let you know.
>
> Joe
>
> Holografix (holografixgmail.com) wrote:
> >
> > Hi
> >
> > Take a look here: http://forums.fedoraforum.org/showthread.php?t=59163
> >
> > I had that problem too.
> >
> > Regards
> > holografix
> >
> >
> > ""Joseph Oaks"" <trelltrells.com> escreveu na mensagem
> > news:20050805.Td6.66325500webmail.trells.com...
> > > So, heres the deal, I'm running Fedora Core 3 on an dual proc AMD64
> > > system.
> > >
> > > I have compiled Apache 2.0.54, and PHP 5.0.4, when I try to start apache
> > > I am given an error. The error is as follows...
> > >
> > > [roothal1 conf]# /etc/rc.d/init.d/httpd start
> > > Starting httpd: Syntax error on line 24 of
> > > /opt/apache-2.0.54/conf/httpd.conf:
> > > Cannot load /opt/apache-2.0.54/modules/libphp5.so into server:
> > > /opt/apache-2.0.54/modules/libphp5.so: cannot restore segment prot after
> > > reloc:
> > > Permission denied
> > >
> > > The only thing I'm finding on google is about /usr/lib64 well I don't have
> > > a
> > > /usr/lib64, its just /usr/lib so that can't be the issue.
> > >
> > > Any suggestion would be appreciated.
> > > thanks
> > >
> > > Joe
> > >
> > > --
> > > "Computers are like air conditioners - they stop working properly when you
> > > open Windows"
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >
> >
>
> --
> "Computers are like air conditioners - they stop working properly when you
> open Windows"
>
>
>
>

--
"Computers are like air conditioners - they stop working properly when you
open Windows"

attached mail follows:

Hi There

I am trying to run a simple password /php / mysql script for a web page and
get the following errors, it works fine on a earlier versions of php / mysql

PHP Notice: Undefined variable: help_out_uid in
/var/www/html/lcc/secure/secure.php on line 87,

PHP Notice: Undefined variable: authed in
/var/www/html/lcc/secure/secure.php on line 34

mysql Ver 11.18 Distrib 3.23.58, for redhat-linux-gnu (i386)

PHP 4.3.9 (cgi) (built: Oct 20 2004 14:52:04)

Thanks for you help

Trevor

attached mail follows:

Trevor Tregoweth wrote:
> Hi There
>
>

point 1: you started a new thread by replying to an existing thread - BAD.
point 2: the errors (notices) are telling you something. read them.
if you don't understand them, try google first, then php.net

hint: your php config has changed - error reporting has been set
to also show E_NOTICE level errors. change it back and you won't see
them any more (they were alway there btw). e.g.

error_reporting( error_reporting() & ^E_NOTICE ); // don't show notices

or set display_errors ini directive in php.ini

> I am trying to run a simple password /php / mysql script for a web page and
> get the following errors, it works fine on a earlier versions of php / mysql
>
>
> PHP Notice: Undefined variable: help_out_uid in
> /var/www/html/lcc/secure/secure.php on line 87,
>
> PHP Notice: Undefined variable: authed in
> /var/www/html/lcc/secure/secure.php on line 34
>
> mysql Ver 11.18 Distrib 3.23.58, for redhat-linux-gnu (i386)
>
> PHP 4.3.9 (cgi) (built: Oct 20 2004 14:52:04)
>
>
>
> Thanks for you help
>
> Trevor
>

attached mail follows:

edwardsplita.org.mo wrote:
>>>How can we define and display the varibles by using for loop
>>>function ?
>>
>><?php
>>for ($x=0;$x<10;$x++){
>> $func[$x]=$x;
>>}
>>print_r($func);
>>?>
>
>
> If I want to define a set of varibles ( two dimension array, eg : $func[0,0] )

$func[0,0] is not valid syntax. you mean $func[0][0]

> and via the varibles of form tag ( format, eg : $_GET["varname"] or
> $_POST["varname"] )...
> How about the example ?

watch what happen to $_POST when you stick these fields in your form
and submit it:

>
> Edward.
>

attached mail follows:

Try using one of the log reader/analysis packages available for Apache or
try doing it urself.
Are you looking for the algorithm? let me know.

On 8/6/05, virtualsoftwaregmail.com <virtualsoftwaregmail.com> wrote:
>
> LOL. This got nothing to do with my question . LOL again
>
> ----- Original Message -----
> From: "Frank de Bot" <phpsearchy.nl>
> Cc: <php-generallists.php.net>
> Sent: Saturday, August 06, 2005 10:20 PM
> Subject: Re: [PHP] Average time spent on a page
>
>
> > virtualsoftwaregmail.com wrote:
> >
> >>Hi,
> >>
> >>How can i found out the average time users spent on a page. Anyone know
> a
> >>tutorial?
> >>
> >>Thanks in advance for your help !!!
> >>
> >
> > A hello world page will take me around 15 secs I guess...
> > A full blown website with everything you can imagine a few months orso.
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>

--
M.Saleh.E.G
97150-4779817

attached mail follows:

Hi,

I'm using Shared Hosting and I was told - then I learned from trial and
error - that you can't use mkdir on Shared Hosting... is this *100%* true?
is
there a way around it?

I get:

Warning: mkdir(/home/***/public_html/test/): Permission denied in
/home/***/public_html/test.php on line 3

So, again, is there any possible way around this? I've Googled, read the
manual but it seems that If I don't get an Error - I get nothing at all,
including the directory.

Thanks for any help!

- Clint

attached mail follows:

As far as I know, it's not a shared hosting issue, but a permission issue.
The site admin has not given the user under which your php scripts run
permission to create directories and most likely files and other file system
operations. It's a security issue.

Robbert

-----Original Message-----
From: Esteamedpwaol.com [mailto:Esteamedpwaol.com]
Sent: Saturday, August 06, 2005 8:53 PM
To: php-generallists.php.net
Subject: [PHP] mkdir, Shared Hosting?

Hi,

I'm using Shared Hosting and I was told - then I learned from trial and
error - that you can't use mkdir on Shared Hosting... is this *100%* true?
is
there a way around it?

I get:

Warning: mkdir(/home/***/public_html/test/): Permission denied in
/home/***/public_html/test.php on line 3

So, again, is there any possible way around this? I've Googled, read the
manual but it seems that If I don't get an Error - I get nothing at all,
including the directory.

Thanks for any help!

- Clint

attached mail follows:

In a message dated 8/6/2005 10:59:44 P.M. Central Standard Time,
phpswimwebs.com writes:

Robbert

I see... I guess I could ask to see if I could get permission to do so then?
lol never hurts to ask :)

Thanks,

Clint

attached mail follows:

Esteamedpwaol.com wrote:
>
> In a message dated 8/6/2005 10:59:44 P.M. Central Standard Time,
> phpswimwebs.com writes:
>
> As far as I know, it's not a shared hosting issue, but a permission issue.
> The site admin has not given the user under which your php scripts run
> permission to create directories and most likely files and other file system
> operations. It's a security issue.
>
> Robbert
>
>
>
> I see... I guess I could ask to see if I could get permission to do so then?
> lol never hurts to ask :)

Open up your FTP client and log into your website, then change the
permissions on your folder so that the apache process has write access
to it. Its really hit and miss depending on your setup.

The sure fire way (but highly insecure) way is to change the permissions
to the directory in question to 777.

A better solution would be 755, but it may not work.

Try it, and see what you get.

attached mail follows:

Um - did you read my last email regarding var_dump var_export and print_r

Did you try them?

Do they do what you want?

On 8/2/05, Adi Zebic <adibeeznest.net> wrote:
> Rory Browne a écrit :
> > I haven't a monkies what that code(your java) does, and I don't have
> > time to analyse it(in expensive cybercafe), but you may want to
> > consider www.php.net/print-r www.php.net/var-dump and
> > www.php.net/var-export
> >
> > I think they may do what you want without using the toString method,
> > which for what you're describing is basicly an ugly hack.
> >
> > One more thing: Enlighten me: What exactly do you mean by "live
> > evolution" in your php/java context.
>
> If in php context you have class, say, A:
>
> class A
> {
>
> var $t1;
> var $t2;
> var $t3;
>
> //After, you have object contructor of type A
> //we have something like this
>
> function A ($var1, $var2, $var3)
> {
> $this -> t1 = $var1;
> $this -> t2 = $var2;
> $this -> t3 = $var3;
> }
>
> ....some other code
> }
>
> //than in some other class we have something like this:
>
> class someOtherClass
> {
> $aConstructor = new A(1,2,3);
> //values of t1, t2 and t3 are 1,2 and 3 now
> }
>
> Right? yes.
>
> How you can you do something like this inside of "someOtherClass"
>
> print ($aConstructor);
>
> to finally have some nice output like
> Value of t1 is 1;
> Value of t2 is 2;
> Value of T3 is 3;
>
> or just:
>
> 1
> 2
> 3
>
> Without creating functions like getValues()
>
> function getValues()
> {
> print ($this -> t1);
> print ($this -> t2);
> print ($this -> t3);
> }
>
> and after explicit invoke function:
>
> $aConstructor -> getValues();
>
> So, what I want is
> this: print ($aConstructor);
>
> and not this:
>
> $aContructor -> getValues();
>
> Am I clear :-)
>
>
> ADI
>
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