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php-general-digest-help
lists.php.net
Date: Sun Sep 16 2007 - 16:24:47 CDT
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]
php-general Digest 16 Sep 2007 21:24:47 -0000 Issue 5022
Topics (messages 262141 through 262149):
php Login script issue
262141 by: Chris Carter
262142 by: Tijnema
262146 by: Sanjeev N
262147 by: Bastien Koert
Re: Configure mail to use Gmail smtp
262143 by: debussy007
262144 by: Thomas Bachmann
262148 by: mike
Re: split in to multiple pages (I think)
262145 by: Thomas Bachmann
Finding next recored in a array
262149 by: Richard Kurth
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----------------------------------------------------------------------
attached mail follows:
Hi,
Its just a login and password validation that I am trying to achieve. If the
username is correct then the person is able to view certain page, if
incorrect then he is directed elsewhere.
<?
$userid=mysql_real_escape_string($userid);
$password=mysql_real_escape_string($password);
if($rec=mysql_fetch_array(mysql_query("SELECT * FROM tablename WHERE
userName='$userName' AND password = '$password'"))){
if(($rec['userName']==$userName)&&($rec['password']==$password)){
include "../include/newsession.php";
echo "<p class=data> <center>Successfully,Logged in<br><br>
logout.php Log OUT <br><br> welcome.php Click here if your browser is not
redirecting automatically or you don't want to wait. <br></center>";
print "<script>";
print " self.location='submit-store-details.php';"; // Comment this
line if you don't want to redirect
print "</script>";
}
}
else {
session_unset();
echo "Wrong Login. Use your correct Userid and Password and Try
<br><center><input type='button' value='Retry'
onClick='history.go(-1)'></center>";
}
?>
I am getting this error when I am using this code:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
resource in thispage.php on line 37
Wrong Login. Use your correct Userid and Password and Try
Why does it show up everytime and whats wrong with mysql_fetch_array().
Please advice also if there is some other way available please help me try
that.
Thanks,
Chris
--
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attached mail follows:
On 9/16/07, Chris Carter <chandan9sharmayahoo.com> wrote:
>
> Hi,
>
> Its just a login and password validation that I am trying to achieve. If the
> username is correct then the person is able to view certain page, if
> incorrect then he is directed elsewhere.
>
> <?
> $userid=mysql_real_escape_string($userid);
Here you call it $userid
> $password=mysql_real_escape_string($password);
>
> if($rec=mysql_fetch_array(mysql_query("SELECT * FROM tablename WHERE
> userName='$userName' AND password = '$password'"))){
and here you call it $userName. If this is the full code, $userName is
not set here, and it would result in query userName='' and mysql_query
will return FALSE, which isn't a valid mysql resource for
mysql_fetch_array.
> if(($rec['userName']==$userName)&&($rec['password']==$password)){
> include "../include/newsession.php";
> echo "<p class=data> <center>Successfully,Logged in<br><br>
> logout.php Log OUT <br><br> welcome.php Click here if your browser is not
> redirecting automatically or you don't want to wait. <br></center>";
> print "<script>";
> print " self.location='submit-store-details.php';"; // Comment this
> line if you don't want to redirect
> print "</script>";
>
> }
> }
> else {
>
> session_unset();
> echo "Wrong Login. Use your correct Userid and Password and Try
> <br><center><input type='button' value='Retry'
> onClick='history.go(-1)'></center>";
>
> }
> ?>
>
> I am getting this error when I am using this code:
>
> Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
> resource in thispage.php on line 37
> Wrong Login. Use your correct Userid and Password and Try
>
> Why does it show up everytime and whats wrong with mysql_fetch_array().
>
> Please advice also if there is some other way available please help me try
> that.
>
> Thanks,
>
> Chris
I advice you to split the code up in 2 seperate actions, and check for errors.
> if($rec=mysql_fetch_array(mysql_query("SELECT * FROM tablename WHERE userName='$userName' AND password = '$password'"))){
would become:
$result = mysql_query("SELECT * FROM tablename WHERE
userName='$userName' AND password = '$password'") or die
(mysql_error());
// You could also add some checks here with mysql_num_rows for example...
if($rec=mysql_fetch_array($result)){
Tijnema
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If this is a mailing list: DO NOT TOP POST! why?:
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Vote for PHP Color Coding (aka Syntax Highlighting) in Gmail! ->
http://gpcc.tijnema.info
attached mail follows:
Hi,
$result = mysql_query("SELECT * FROM tablename WHERE
userName='$userName' AND password = '$password'");
if($rec = mysql_fetch_array($result)){
//your code
}
Try like this it may solve. It may solve your problem
Don't try to fetch the result from one single line code.
Warm Regards,
Sanjeev
http://www.sanchanworld.com/
http://webdirectory.sanchanworld.com - Submit your website URL
http://webhosting.sanchanworld.com - Choose your best web hosting plan
-----Original Message-----
From: Chris Carter [mailto:chandan9sharmayahoo.com]
Sent: Sunday, September 16, 2007 3:10 PM
To: php-generallists.php.net
Subject: [PHP] php Login script issue
Hi,
Its just a login and password validation that I am trying to achieve. If the
username is correct then the person is able to view certain page, if
incorrect then he is directed elsewhere.
<?
$userid=mysql_real_escape_string($userid);
$password=mysql_real_escape_string($password);
if($rec=mysql_fetch_array(mysql_query("SELECT * FROM tablename WHERE
userName='$userName' AND password = '$password'"))){
if(($rec['userName']==$userName)&&($rec['password']==$password)){
include "../include/newsession.php";
echo "<p class=data> <center>Successfully,Logged in<br><br>
logout.php Log OUT <br><br> welcome.php Click here if your browser is not
redirecting automatically or you don't want to wait. <br></center>";
print "<script>";
print " self.location='submit-store-details.php';"; // Comment this
line if you don't want to redirect
print "</script>";
}
}
else {
session_unset();
echo "Wrong Login. Use your correct Userid and Password and Try
<br><center><input type='button' value='Retry'
onClick='history.go(-1)'></center>";
}
?>
I am getting this error when I am using this code:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
resource in thispage.php on line 37
Wrong Login. Use your correct Userid and Password and Try
Why does it show up everytime and whats wrong with mysql_fetch_array().
Please advice also if there is some other way available please help me try
that.
Thanks,
Chris
--
View this message in context:
http://www.nabble.com/php-Login-script-issue-tf4450691.html#a12698139
Sent from the PHP - General mailing list archive at Nabble.com.
--
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To unsubscribe, visit: http://www.php.net/unsub.php
attached mail follows:
argh! hotmail sucks
I don't see in the script where you are using $_POST / $_GET / $_REQUEST to access tha data from the form. Its likely that the example you are following is old and uses 'register_globals'. Since register_globals is a huge security hole and is not active in any new installations of PHP you need to change your script to use the above methods to get the form data. The error you are getting is due to the fact that you are not passing in the values to the sql and not getting a valid result
Note that the below example fixes your issue but DOES NOT do any validation, which you really should do before passing your data to the sql...
$userid=mysql_real_escape_string($_POST['userid']);
$password=mysql_real_escape_string($_POST['password']);
if($rec=mysql_fetch_array(mysql_query("SELECT * FROM tablename WHERE> userName='$userName' AND password = '$password'"))){
if(($rec['userName']==$userName)&&($rec['password']==$password))
bastien
----------------------------------------> Date: Sun, 16 Sep 2007 02:39:57 -0700> From: chandan9sharmayahoo.com> To: php-generallists.php.net> Subject: [PHP] php Login script issue>>> Hi,>> Its just a login and password validation that I am trying to achieve. If the> username is correct then the person is able to view certain page, if> incorrect then he is directed elsewhere.>> $userid=mysql_real_escape_string($userid);> $password=mysql_real_escape_string($password);>> if($rec=mysql_fetch_array(mysql_query("SELECT * FROM tablename WHERE> userName='$userName' AND password = '$password'"))){> if(($rec['userName']==$userName)&&($rec['password']==$password)){> include "../include/newsession.php";> echo " Successfully,Logged in> logout.php Log OUT welcome.php Click here if your browser is not> redirecting automatically or you don't want to wait. ";> print "";>> }> }> else {>> session_unset();> echo "Wrong Login. Use your correct Userid and Password and Try> onClick='history.go(-1)'>";>> }> ?>>> I am getting this error when I am using this code:>> Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result> resource in thispage.php on line 37> Wrong Login. Use your correct Userid and Password and Try>> Why does it show up everytime and whats wrong with mysql_fetch_array().>> Please advice also if there is some other way available please help me try> that.>> Thanks,>> Chris> --> View this message in context: http://www.nabble.com/php-Login-script-issue-tf4450691.html#a12698139> Sent from the PHP - General mailing list archive at Nabble.com.>> --> PHP General Mailing List (http://www.php.net/)> To unsubscribe, visit: http://www.php.net/unsub.php>
_________________________________________________________________
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attached mail follows:
I succeeded using the Zend Framework.
debussy007 wrote:
>
> Hello,
>
> I have read here : http://www.geekzone.co.nz/tonyhughes/599
> that I can use Gmail as a free SMTP server.
>
> Is it possible to change the php.ini in order to have this running ?
>
> I need to specify in some way the following :
>
> Outgoing Mail (SMTP) Server - requires TLS: smtp.gmail.com (use
> authentication)
> Use Authentication: Yes
> Use STARTTLS: Yes (some clients call this SSL)
> Port: 465 or 587
> Account Name: your Gmail username (including 'gmail.com')
> Email Address: your original isp address (usernameisp.c0m)
> Password: your Gmail password
>
>
>
> I can see in the php.ini that I can specify the port, smtp server and the
> from.
>
> But how do I do for he other parameters ?
>
> Thank you !!
>
--
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attached mail follows:
ZF rocks ;)
debussy007 schrieb:
> I succeeded using the Zend Framework.
>
>
>
> debussy007 wrote:
>> Hello,
>>
>> I have read here : http://www.geekzone.co.nz/tonyhughes/599
>> that I can use Gmail as a free SMTP server.
>>
>> Is it possible to change the php.ini in order to have this running ?
>>
>> I need to specify in some way the following :
>>
>> Outgoing Mail (SMTP) Server - requires TLS: smtp.gmail.com (use
>> authentication)
>> Use Authentication: Yes
>> Use STARTTLS: Yes (some clients call this SSL)
>> Port: 465 or 587
>> Account Name: your Gmail username (including 'gmail.com')
>> Email Address: your original isp address (usernameisp.c0m)
>> Password: your Gmail password
>>
>>
>>
>> I can see in the php.ini that I can specify the port, smtp server and the
>> from.
>>
>> But how do I do for he other parameters ?
>>
>> Thank you !!
>>
>
attached mail follows:
i'm quite sure you can't with php's built-in mail() function.
however more advanced modules should support it. look in PEAR, google
for phpmailer, etc. i'm sure there's got to be some. worst case i
think you have all the tools in PHP to make your own anyway.
On 9/16/07, debussy007 <debussy007gmail.com> wrote:
> debussy007 wrote:
> >
> > Hello,
> >
> > I have read here : http://www.geekzone.co.nz/tonyhughes/599
> > that I can use Gmail as a free SMTP server.
> >
> > Is it possible to change the php.ini in order to have this running ?
> >
> > I need to specify in some way the following :
> >
> > Outgoing Mail (SMTP) Server - requires TLS: smtp.gmail.com (use
> > authentication)
> > Use Authentication: Yes
> > Use STARTTLS: Yes (some clients call this SSL)
> > Port: 465 or 587
> > Account Name: your Gmail username (including 'gmail.com')
> > Email Address: your original isp address (usernameisp.c0m)
> > Password: your Gmail password
> >
> >
> >
> > I can see in the php.ini that I can specify the port, smtp server and the
> > from.
> >
> > But how do I do for he other parameters ?
> >
> > Thank you !!
attached mail follows:
Why don't post an example of your news file too?
Joker7 schrieb:
> Hi,
> I'm using the code below to display news articles-which works great apart
> from. I can control the number of articles,but I would like to add a link to
> the bottom of the page to the un-displayed articles ( nexted 5 articles and
> so on) any pointers would be most welcome as most know my PHP skills are not
> the best :).
>
> Cheers
> Chris
>
>
> <?
>
> $max_latest = 5;
> $filename = "articlesum.php";
>
> #- open article
> if(file_exists($filename)){
> $fh = fopen($filename, "r");
> $old_news = fread($fh, filesize($filename));
> fclose($fh);
> }
> #- get article
> $articles = explode("<!--ARTICLE-->", $old_news);
>
> $i=0;
> foreach ( $articles as $article ){
> if(count($articles)>$i){
> if($max_latest >= $i++){
> print $article;
> }
> }
> }
>
> ?>
attached mail follows:
$Campaign_array| = array('0','1','3','5','8','15','25');|
I know that I can find the next recored in a array using next. What I do
not understand is if I know the last number was say 5 how do I tell the
script that that is the current number so I can select the next record
||
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